Math Problem Statement

find f of g given that f(x)=x-2 and g(x)=sin(x)+tan(x)

Solution

To find f(g(x))f(g(x)), we substitute g(x)g(x) into the function f(x)f(x).

Given:

  • f(x)=x2f(x) = x - 2
  • g(x)=sin(x)+tan(x)g(x) = \sin(x) + \tan(x)

We substitute g(x)g(x) into f(x)f(x):

f(g(x))=f(sin(x)+tan(x))f(g(x)) = f(\sin(x) + \tan(x))

Now, using the definition of f(x)f(x), replace xx with sin(x)+tan(x)\sin(x) + \tan(x):

f(g(x))=(sin(x)+tan(x))2f(g(x)) = (\sin(x) + \tan(x)) - 2

So, the composition function is:

f(g(x))=sin(x)+tan(x)2f(g(x)) = \sin(x) + \tan(x) - 2

Let me know if you'd like further details or if you have any questions.

Here are 5 related questions:

  1. What is the domain of f(g(x))f(g(x))?
  2. How would you find g(f(x))g(f(x)) using the given functions?
  3. How do the trigonometric properties of sin(x)\sin(x) and tan(x)\tan(x) affect the behavior of f(g(x))f(g(x))?
  4. What happens if we differentiate f(g(x))f(g(x))?
  5. What are the zeros of f(g(x))f(g(x))?

Tip: Always check the domains of composite functions to ensure they are well-defined.

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Math Problem Analysis

Mathematical Concepts

Functions
Trigonometry
Composition of Functions

Formulas

f(x) = x - 2
g(x) = sin(x) + tan(x)
f(g(x)) = f(sin(x) + tan(x)) = (sin(x) + tan(x)) - 2

Theorems

Function Composition

Suitable Grade Level

Grades 10-12