Math Problem Statement

Выполните действия с комплексными числами, включая сложение, вычитание, умножение и возведение в степень.

Solution

The given tasks consist of arithmetic operations involving complex numbers. Below is the breakdown of the operations and general instructions:


Explanation of Tasks

  1. Addition/Subtraction of Complex Numbers
    Form: (a+bi)+(c+di)(a + bi) + (c + di) or (a+bi)(c+di)(a + bi) - (c + di),
    where real and imaginary parts are added/subtracted separately:
    (a+c)+(b+d)i(a + c) + (b + d)i

  2. Multiplication of Complex Numbers
    Apply distributive property (a+bi)(c+di)(a + bi)(c + di):
    (a+bi)(c+di)=ac+adi+bci+bdi2(a + bi)(c + di) = ac + adi + bci + bdi^2 Recall i2=1i^2 = -1.

  3. Multiplication by a Real Number
    Multiply each part of the complex number by the real number.

  4. Powers of Complex Numbers
    Use:

    • Square: Expand (a+bi)2(a + bi)^2 using (a+bi)(a+bi)(a + bi)(a + bi).
    • Cube: Expand step by step.
  5. Expression with Differences of Squares
    Recognize (a+b)(ab)=a2b2(a + b)(a - b) = a^2 - b^2, where i2=1i^2 = -1.


Solutions of the Problems

I will solve a couple of tasks below and can proceed with others upon request.


  1. (3 + 5i) + (7 - 2i)
    Add real and imaginary parts:
    (3+7)+(52)i=10+3i(3 + 7) + (5 - 2)i = 10 + 3i

  2. (-2 + 3i) - (7 - 2i)
    Subtract real and imaginary parts:
    (27)+(3(2))i=9+5i(-2 - 7) + (3 - (-2))i = -9 + 5i

  3. (3 - 2i) + (5 + i)
    Add real and imaginary parts:
    (3+5)+(2+1)i=8i(3 + 5) + (-2 + 1)i = 8 - i

  4. (-5 + 2i) + (5 + 2i)
    Add real and imaginary parts:
    (5+5)+(2+2)i=0+4ior simply 4i(-5 + 5) + (2 + 2)i = 0 + 4i \quad \text{or simply } 4i

  5. (2 + 3i)(5 - 7i)
    Use distributive property:
    (2)(5)+(2)(7i)+(3i)(5)+(3i)(7i)(2)(5) + (2)(-7i) + (3i)(5) + (3i)(-7i) Simplify each term:
    1014i+15i21i210 - 14i + 15i - 21i^2 Since i2=1i^2 = -1:
    1014i+15i+21=31+i10 - 14i + 15i + 21 = 31 + i


Would you like me to solve the rest or any specific part in detail? Let me know!


Related Questions

  1. How do you multiply two complex numbers?
  2. What is the process for squaring a complex number?
  3. How does the imaginary unit ii work in powers like i2i^2 or i3i^3?
  4. How can you identify and simplify expressions involving conjugates?
  5. What is the modulus of a complex number?

Tip:

Remember that i2=1i^2 = -1 is a fundamental property in all complex number operations. It helps simplify terms involving i2i^2, i3i^3, etc.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Addition and Subtraction of Complex Numbers
Multiplication of Complex Numbers
Powers of Complex Numbers
Properties of the Imaginary Unit i

Formulas

(a + bi) + (c + di) = (a + c) + (b + d)i
(a + bi)(c + di) = ac + adi + bci + bdi^2 (where i^2 = -1)
(a + b)(a - b) = a^2 - b^2

Theorems

Distributive Property of Complex Numbers
Square of the Binomial Theorem
Properties of Imaginary Unit i (i^2 = -1)

Suitable Grade Level

Grades 9-11