Math Problem Statement

answer this

Use the graph of the function to complete the table.

Solution

To fill in the missing value in the table, we can analyze the graph and find the function's behavior.

Step 1: Identify the Slope

The line on the graph passes through the points:

  • (2,5)(2, 5)
  • (8,1)(8, 1)

Using the formula for slope m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, where (x1,y1)=(2,5)(x_1, y_1) = (2, 5) and (x2,y2)=(8,1)(x_2, y_2) = (8, 1): m=1582=46=23m = \frac{1 - 5}{8 - 2} = \frac{-4}{6} = -\frac{2}{3}

Step 2: Write the Equation of the Line

Since the slope mm is 23-\frac{2}{3}, we can use the point-slope form yy1=m(xx1)y - y_1 = m(x - x_1) with point (2,5)(2, 5) to get: y5=23(x2)y - 5 = -\frac{2}{3}(x - 2) Expanding this equation: y5=23x+43y - 5 = -\frac{2}{3}x + \frac{4}{3} y=23x+43+5y = -\frac{2}{3}x + \frac{4}{3} + 5 Converting 5 to a fraction 153\frac{15}{3}, we get: y=23x+193y = -\frac{2}{3}x + \frac{19}{3}

Step 3: Find the Missing Output for x=5x = 5

Now, substitute x=5x = 5 into the equation: y=23(5)+193y = -\frac{2}{3}(5) + \frac{19}{3} y=103+193=93=3y = -\frac{10}{3} + \frac{19}{3} = \frac{9}{3} = 3

Final Answer

The missing output value when the input is 55 is 33.

Completed Table:

InputOutput
25
53
81

Would you like further details on this process, or do you have any other questions?


  1. What is the importance of the slope in finding the equation of a line?
  2. How does the point-slope form of a line differ from the slope-intercept form?
  3. Can you use two points to find the equation of any line?
  4. Why is the function here represented by a straight line?
  5. How does changing the slope affect the line on the graph?

Tip: When interpreting graphs, identifying two points and calculating the slope is an effective way to derive the function’s equation.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Graph Interpretation
Slope Calculation

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Point-slope form: y - y1 = m(x - x1)

Theorems

Linear equation theorem

Suitable Grade Level

Grade 8