Math Problem Statement

Complete the table for the function f(b) = |6b| with values of b = -1, 0, 1, 2.

Solution

The function provided is f(b)=6bf(b) = |6b|, which means the absolute value of 6b6b. Let's calculate f(b)f(b) for each value of bb in the table:

  1. For b=1b = -1: f(1)=6(1)=6=6f(-1) = |6(-1)| = |-6| = 6

  2. For b=0b = 0: f(0)=6(0)=0=0f(0) = |6(0)| = |0| = 0

  3. For b=1b = 1: f(1)=6(1)=6=6f(1) = |6(1)| = |6| = 6

  4. For b=2b = 2: f(2)=6(2)=12=12f(2) = |6(2)| = |12| = 12

So the completed table is:

| bb | f(b)=6bf(b) = |6b| | |---------|------------------| | -1 | 6 | | 0 | 0 | | 1 | 6 | | 2 | 12 |

Would you like more details or explanations on how I calculated these values?

Here are 5 related questions to consider:

  1. How does the absolute value function affect negative numbers?
  2. What is the general form of an absolute value function?
  3. What happens to the function values when multiplying different constants with bb?
  4. How would the function change if it were f(b)=6bf(b) = 6b (without the absolute value)?
  5. How would the results differ if we calculated f(b)=bf(b) = |b| instead?

Tip: Always simplify inside the absolute value before applying the function to avoid confusion.

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Functions

Formulas

f(b) = |6b|

Theorems

Absolute Value Theorem

Suitable Grade Level

Grade 8-9