x : 1.72,0.96,0.20 y:0.60,1.48,2.36. when comparing X and Y, which buries the most what's the value of the statistic

To determine which variable, \( X \) or \( Y \), exhibits more variability, we can compare the **variance** or **standard deviation** of each dataset. Variance and standard deviation are measures of how spread out the values are around the mean.

Let me first compute the mean and standard deviation for both \( X \) and \( Y \), and then compare their variability.

The values you provided are:

- \( X = \{1.72, 0.96, 0.20\} \)
- \( Y = \{0.60, 1.48, 2.36\} \)

I'll calculate the **standard deviation** (which is the square root of the variance) for both datasets.For the given dataFor the given 

- The mean of \( X \) is \( 0.96 \), and its standard deviation is \( 0.76 \).
- The mean of \( Y \) is \( 1.48 \), and its standard deviation is \( 0.88 \).

Since the standard deviation of \( Y \) (0.88) is higher than that of \( X \) (0.76), we can conclude that \( Y \) shows more variability compared to \( X \).

If you have any further questions or want more details, feel free to ask!

Here are 5 related questions you might find helpful:
1. How is standard deviation calculated?
2. What is the difference between variance and standard deviation?
3. Why do we use the sample standard deviation (ddof=1) in statistics?
4. How does mean affect the comparison of datasets' variability?
5. What other measures can be used to compare the spread of data?

**Tip:** Standard deviation provides a sense of how spread out your data is. The larger the value, the more dispersed the data points are around the mean.

x : 1.72, 0.96, 0.20 y: 0.60, 1.48, 2.36. When comparing X and Y, which varies the most and what's the value of the statistic?

Compare the variability between two datasets X = {1.72, 0.96, 0.20} and Y = {0.60, 1.48, 2.36} by calculating their standard deviations. Learn how to assess which dataset shows more spread using key statistical concepts. Suitable for Grades 9-12.

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