Math Problem Statement
A small animal veterinarian reviews her records for the day and notes that she has seen eight dogs and eight cats with the following weights (in pounds).
Dogs: 12, 21, 39, 44, 52, 61, 74, 102
Cats: 4, 5, 8, 12, 15, 19, 23, 23
a. Before analyzing these data sets, make a conjecture about which set has the larger mean, median, and standard deviation. Explain your reasoning.
b. Compute the mean and standard deviation of each set.
Question content area bottom
Part 1
a. Make correct conjectures below about which set has the larger mean, median, and standard deviation. Choose the correct answer below.
A.
The mean, median, and standard deviation are all higher for cats because there is less variation in the weights, so the average value, middle value, and spread must be larger.
B.
The mean and median are higher for cats because there is less variation in the weights. The standard deviation is higher for dogs because there is more variation in the weights.
C.
The mean, median, and standard deviation are all higher for dogs because most of the weights are larger, so the average value, middle value, and spread must be larger.
D.
The mean and median are higher for dogs because most of the weights are larger, so the average value and middle value must be larger. The standard deviation is higher for cats because there is more variation in the weights.
Solution
Part 1a. Conjecture about the mean, median, and standard deviation:
Let's analyze the data sets before calculating the actual values.
- Dogs: The weights range from 12 to 102 pounds, with a significant spread between the minimum and maximum values. This suggests a larger mean and median compared to cats. Also, the large variation in dog weights suggests a higher standard deviation.
- Cats: The weights range from 4 to 23 pounds, with less variation compared to the dog weights. The cat weights are generally smaller, so the mean and median are likely smaller. The relatively small spread of the data suggests a lower standard deviation.
Therefore, based on this reasoning, we can conclude:
- The mean and median are likely higher for dogs because the weights are generally larger.
- The standard deviation is also likely higher for dogs because the variation (spread of the data) is greater.
The best conjecture is: C. The mean, median, and standard deviation are all higher for dogs because most of the weights are larger, so the average value, middle value, and spread must be larger.
Part 1b. Compute the mean and standard deviation:
We can now calculate the mean and standard deviation for each data set (dogs and cats).
Dogs:
Weights: 12, 21, 39, 44, 52, 61, 74, 102
- Mean:
- Standard deviation: We will use the formula:
Cats:
Weights: 4, 5, 8, 12, 15, 19, 23, 23
- Mean:
- Standard deviation: Using the same formula.
Let me calculate these values.### Computed Values:
-
Dogs:
- Mean: 50.63 pounds
- Standard deviation: 28.89 pounds
-
Cats:
- Mean: 13.63 pounds
- Standard deviation: 7.63 pounds
Conclusion:
- The mean and standard deviation for dogs are significantly higher than for cats.
- This confirms the conjecture in option C: The mean, median, and standard deviation are all higher for dogs.
Would you like a more detailed breakdown or explanation of these calculations?
Related Questions:
- How does the range of data affect the standard deviation?
- What are other measures of central tendency besides mean and median?
- How can outliers influence the mean and standard deviation?
- What is the significance of using the sample standard deviation (with )?
- How do you interpret the difference in variability between two data sets?
Tip:
Always use the sample standard deviation (with ) when working with a sample of data, rather than the entire population, to avoid underestimating the variability.
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Math Problem Analysis
Mathematical Concepts
Descriptive Statistics
Measures of Central Tendency
Standard Deviation
Formulas
Mean: (Sum of all values) / (Number of values)
Sample Standard Deviation: sqrt( (1 / (n - 1)) * sum((x_i - mean)^2) )
Theorems
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Suitable Grade Level
Grades 10-12
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