Comparing mean and median, it is discovered:

(A) mean > median

(B) mean < median

(C) mean = median

(D) mean = SD

(E) none of these

The correct answer is:

**(A) mean > median**

This situation generally occurs when the data is **positively skewed**. In positively skewed (or right-skewed) distributions, the mean is typically greater than the median because the mean is pulled in the direction of the skew by the larger values in the dataset.

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Here are 5 related questions for deeper understanding:
1. What is the relationship between mean, median, and mode in a negatively skewed distribution?
2. How does outlier data affect the mean compared to the median?
3. Can the median ever be larger than the mean in a dataset? In what situation?
4. What does the skewness of a distribution indicate about the data?
5. How can one determine if a distribution is symmetric?

**Tip:** The mean is sensitive to extreme values, while the median is more robust and resistant to outliers.

Comparing mean and median, it is discovered: (A) mean > median (B) mean < median (C) mean = median (D) mean = SD (E) none of these

Understand the relationship between mean and median in various data distributions. This example shows how in a positively skewed distribution, the mean is typically greater than the median. Explore key statistical concepts, including central tendency and skewness. Suitable for Grades 9-12.

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