Math Problem Statement

based on the graph, answer the question

Based on the graph, answer the question

Solution

The graph provided compares different runtime functions. The curves for T(n)=2logn+1T(n) = 2 \log n + 1, fA(n)=2f_A(n) = 2, and fB(n)=2n+1f_B(n) = 2n + 1 are plotted. Based on the descriptions in the second image and the data from the graph, I can analyze the functions as follows:

  1. fC(n)=2n0.5+1f_C(n) = 2n^{0.5} + 1 grows faster than T(n)=2logn+1T(n) = 2 \log n + 1 as nn increases:

    • This is true. The curve for fC(n)=2n0.5+1f_C(n) = 2n^{0.5} + 1 grows faster than T(n)=2logn+1T(n) = 2 \log n + 1, which shows a logarithmic increase. In comparison, fC(n)f_C(n) exhibits a growth rate faster than logarithmic as nn increases.
  2. At around n=10000n = 10000 and beyond, fB(n)=2n+1f_B(n) = 2n + 1 has a (way) slower runtime than all of the three functions T(n),fA(n),T(n), f_A(n), and fC(n)f_C(n):

    • This is false. From the graph, fB(n)=2n+1f_B(n) = 2n + 1 increases linearly, and it clearly grows faster than the constant fA(n)=2f_A(n) = 2 and logarithmic T(n)=2logn+1T(n) = 2 \log n + 1, and slower than fC(n)f_C(n). However, it does not have a slower runtime than all of the functions.
  3. fC(n)=2n0.5+1f_C(n) = 2n^{0.5} + 1 grows faster than fB(n)=2n+1f_B(n) = 2n + 1 as nn increases:

    • This is false. fB(n)=2n+1f_B(n) = 2n + 1 grows linearly, while fC(n)=2n0.5+1f_C(n) = 2n^{0.5} + 1 grows at a rate slower than linear, so it does not grow faster than fB(n)f_B(n).
  4. T(n)=2n+1T(n) = 2n + 1 will have the same value as fA(n)=2f_A(n) = 2 somewhere within the interval n[2,)n \in [2, \infty):

    • This is true. The function T(n)=2n+1T(n) = 2n + 1 is a linear function, and since fA(n)=2f_A(n) = 2 is a constant, they will indeed intersect at some point in the interval as the values of T(n)T(n) and fA(n)f_A(n) converge.

Based on this analysis, the two true statements are:

  • fC(n)=2n0.5+1f_C(n) = 2n^{0.5} + 1 grows faster than T(n)=2logn+1T(n) = 2 \log n + 1 as nn increases.
  • T(n)=2n+1T(n) = 2n + 1 will have the same value as fA(n)=2f_A(n) = 2 somewhere within the interval n[2,)n \in [2, \infty).

Would you like further explanations or assistance with other concepts related to these functions?

Here are some follow-up questions you might find useful:

  1. What is the exact point where T(n)=2n+1T(n) = 2n + 1 intersects fA(n)=2f_A(n) = 2?
  2. How can we determine the growth rate of a function from its graph?
  3. What are the practical applications of logarithmic and linear growth in algorithms?
  4. How does the addition of n0.5n^{0.5} in fC(n)f_C(n) affect its runtime complexity compared to linear growth?
  5. Can you describe how logarithmic growth compares to polynomial growth in terms of computational cost?

Tip: To compare growth rates, you can often use big-O notation to analyze how different functions scale with large inputs.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Asymptotic Analysis
Big-O Notation
Function Growth

Formulas

T(n) = 2logn + 1
f_A(n) = 2
f_B(n) = 2n + 1
f_C(n) = 2n^0.5 + 1

Theorems

Growth rate comparison
Logarithmic vs. Linear growth

Suitable Grade Level

Grades 10-12