Math Problem Statement

H is the midpoint of IG. J is the midpoint of IK. IG = GK = 10. Compare Quantity A (IJ) with Quantity B (5).

Solution

We are given a geometric figure and some information about points and midpoints. Let's break it down:

  1. Givens:

    • HH is the midpoint of IGIG.
    • JJ is the midpoint of IKIK.
    • IG=GK=10IG = GK = 10.
  2. Analysis:

    • Since HH is the midpoint of IGIG, the length of IH=HG=5IH = HG = 5 (half of IGIG).
    • Similarly, JJ is the midpoint of IKIK, but we don't yet know IKIK. However, we can calculate the length of IJIJ based on the relationship between the points.
  3. Focus on IJIJ:

    • By the Midpoint Theorem (in a triangle, the segment joining the midpoints of two sides is parallel to the third side and half as long), IJIJ is half the length of GKGK, which is 10.
    • Therefore, IJ=12×10=5IJ = \frac{1}{2} \times 10 = 5.
  4. Comparing Quantities:

    • Quantity A is IJIJ, which is 5.
    • Quantity B is given as 5.

Since IJ=5IJ = 5 and Quantity B is also 5, the two quantities are equal.

Correct answer:

  • The two quantities are equal.\boxed{\text{The two quantities are equal.}}

Would you like further details or have any questions?

Here are 5 related questions to explore:

  1. What is the Midpoint Theorem, and how is it applied?
  2. How would the answer change if the value of GKGK were different?
  3. What if HH were not the midpoint of IGIG? How would it affect the solution?
  4. Can the length of IKIK be determined from the given information?
  5. What other properties of triangles and midpoints can be useful in geometry problems?

Tip: Always check if midpoints create relationships like parallel lines or proportional segments in triangles, as they often simplify the problem.

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Math Problem Analysis

Mathematical Concepts

Geometry
Midpoints
Triangles

Formulas

Midpoint Theorem

Theorems

Midpoint Theorem: In a triangle, the segment joining the midpoints of two sides is parallel to the third side and half as long.

Suitable Grade Level

Grades 9-10