Math Problem Statement

A geometric sequence has a third term of -108 and an eighth term of 26,244. What is the common ratio between sequence values?

Solution

To find the common ratio rr of the geometric sequence, we can use the information given:

  • The third term a3=108a_3 = -108
  • The eighth term a8=26,244a_8 = 26,244

For a geometric sequence, the nn-th term is given by the formula: an=arn1a_n = a \cdot r^{n-1} where aa is the first term, and rr is the common ratio.

Step 1: Set up equations

Using the third term: ar2=108a \cdot r^{2} = -108 Using the eighth term: ar7=26,244a \cdot r^{7} = 26,244

Step 2: Divide the equations to eliminate aa

Dividing the second equation by the first: ar7ar2=26,244108\frac{a \cdot r^{7}}{a \cdot r^{2}} = \frac{26,244}{-108} This simplifies to: r5=26,244108r^{5} = \frac{26,244}{-108}

Step 3: Calculate r5r^{5}

r5=243r^{5} = -243

Step 4: Find rr by taking the fifth root

The fifth root of 243-243 is 3-3.

Answer

The common ratio rr is 3\mathbf{-3}.

Let me know if you'd like more details or have any questions!

Here are some related questions to practice:

  1. How would you find the first term of this sequence given the third term and common ratio?
  2. What would the tenth term of this sequence be?
  3. How do you determine if a sequence is geometric?
  4. What is the formula to sum the first nn terms of a geometric sequence?
  5. How would the solution change if the eighth term were negative?

Tip: In a geometric sequence, dividing two consecutive terms gives the common ratio.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Exponents

Formulas

nth term formula of a geometric sequence: a_n = a * r^(n-1)

Theorems

-

Suitable Grade Level

Grades 9-12