To solve this problem, we need to determine how many ways there are to fill the five committee positions based on the number of candidates for each role. Let’s analyze the options:

1. Faculty member: There are 2 people interested (Mrs. Johnson, Dr. Nelson).
2. Male student: There are 3 people interested (Hans, Chau, Alan).
3. Female student: There are 4 people interested (Ann, Elsa, Karen).
4. Parent: There are 5 people interested (Mrs. Ramirez, Ms. Jones, Dr. Rogers, Mr. Thomas).
5. School board member: There are 5 people interested (Mr. Davis, Mrs. Russell, Ms. Perez, Dr. Ross).

To find the total number of ways to fill these positions, we multiply the number of options for each category:

$2 \times 3 \times 4 \times 5 \times 5 = 600$

Thus, there are 600 different ways to fill the five committee positions.

Do you need any further details or explanations? Here are five related questions for further exploration:

1. What if a specific person is required to fill one of the positions? How would that affect the total number of combinations?
2. How many ways can the committee be formed if two of the positions had only one candidate each?
3. If one person can only serve in one position, how does that limit the choices?
4. What if there were an additional requirement for a certain gender balance on the committee?
5. How would the total number change if one position could also be left unfilled?

Tip: When solving combination problems, breaking down each choice and multiplying them together is a common and efficient approach.