Math Problem Statement

Rework problem 15 from section 2.3 of your text, involving the vegetable and fruit salads. Assume that you have 6 different types of vegetables and 7 different types of fruit. A vegetable salad consists of a mixture of any 2 types of vegetables, and a fruit salad consists of a mixture of 4 kinds of fruit. (1) In how many different ways can you prepare a vegetable salad and a fruit salad? 525 (2) In how many different ways can you prepare a vegetable salad or a fruit salad but not both? 50 (3) How many ways can you choose two different kinds of salad?

Solution

Let's work through this problem step by step. Here's the breakdown:

Given Information:

  • 6 different types of vegetables
  • 7 different types of fruit
  • Vegetable salad consists of a mixture of any 2 types of vegetables.
  • Fruit salad consists of a mixture of any 4 kinds of fruit.

We need to address the three questions:

Part 1: In how many different ways can you prepare a vegetable salad and a fruit salad?

To prepare a vegetable salad, you must choose 2 types of vegetables from the 6 available. The number of ways to choose 2 vegetables from 6 is given by the binomial coefficient: (62)=6×52×1=15\binom{6}{2} = \frac{6 \times 5}{2 \times 1} = 15

To prepare a fruit salad, you must choose 4 types of fruit from the 7 available. The number of ways to choose 4 fruits from 7 is given by: (74)=(73)=7×6×53×2×1=35\binom{7}{4} = \binom{7}{3} = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} = 35

The total number of ways to prepare both a vegetable salad and a fruit salad is the product of the two: Total (both)=(62)×(74)=15×35=525\text{Total (both)} = \binom{6}{2} \times \binom{7}{4} = 15 \times 35 = 525

Part 2: In how many different ways can you prepare a vegetable salad or a fruit salad, but not both?

Here we are asked to find the number of ways to prepare either a vegetable salad or a fruit salad, but not both. This is the sum of the individual choices for vegetable and fruit salads, excluding the case where both are chosen.

So, we simply add the number of ways to choose just a vegetable salad and the number of ways to choose just a fruit salad: Vegetable salad only=(62)=15\text{Vegetable salad only} = \binom{6}{2} = 15 Fruit salad only=(74)=35\text{Fruit salad only} = \binom{7}{4} = 35 Total (either but not both)=(62)+(74)=15+35=50\text{Total (either but not both)} = \binom{6}{2} + \binom{7}{4} = 15 + 35 = 50

Part 3: How many ways can you choose two different kinds of salad?

Here we are asked how many ways we can choose two different kinds of salad. Since the problem implies we're choosing both a vegetable salad and a fruit salad, this is essentially the same question as Part 1.

So, the answer is the same: 525\boxed{525}


Summary of Results:

  1. Number of ways to prepare a vegetable salad and a fruit salad: 525
  2. Number of ways to prepare a vegetable salad or a fruit salad, but not both: 50
  3. Number of ways to choose two different kinds of salad: 525

Would you like further details on any of these calculations, or have any additional questions?

Relative Questions:

  1. What is the meaning of binomial coefficients and how are they calculated?
  2. How would the problem change if we had 8 types of fruits instead of 7?
  3. Can you solve this problem using combinations and permutations?
  4. How would the solution change if we needed to select 3 types of vegetables instead of 2?
  5. Can we calculate the number of ways to make a salad if we could repeat types of vegetables or fruits?

Tip:

Whenever you are dealing with combinations, remember that the order of selection does not matter. This is the key difference between combinations and permutations!

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Combinations
Binomial Coefficient

Formulas

C(n, k) = n! / (k!(n-k)!)
C(6, 2) = 6! / (2!(6-2)!)
C(7, 4) = 7! / (4!(7-4)!)

Theorems

Binomial Coefficient Theorem

Suitable Grade Level

Grades 9-12