Math Problem Statement

In a fair day, the school connects 6 flags with ropes to divide the playground into 3 smaller areas. The school can choose the color of each flag among red, blue, yellow, or purple so that any 2 consecutive flags do not have the same colors. In how many different ways can the flags be planted?

Solution

The problem involves placing 6 flags in a circular arrangement with 4 available colors: red, blue, yellow, and purple. The flags must be colored so that no two consecutive flags have the same color.

Step-by-Step Solution

  1. Identify the Structure: Since there are 6 flags arranged in a loop, the arrangement must be treated as circular rather than linear. This circular restriction means that the color of the last flag must also be different from the first flag.

  2. Choose Colors for the First Flag: There are 4 choices for the color of the first flag.

  3. Color Choices for the Remaining Flags: For each subsequent flag, we can choose any of the remaining 3 colors (to avoid matching the color of the previous flag).

    • Flag 2: 3 choices (must be different from Flag 1)
    • Flag 3: 3 choices (must be different from Flag 2)
    • Flag 4: 3 choices (must be different from Flag 3)
    • Flag 5: 3 choices (must be different from Flag 4)
    • Flag 6: 3 choices (must be different from Flag 5)
  4. Consider the Circular Condition: After choosing colors for Flags 1 to 6, we must ensure that Flag 6’s color is different from Flag 1’s color to complete the loop without any two consecutive flags sharing the same color.

  5. Calculating the Total Possibilities: Without the circular condition, the total number of color arrangements would be: 4×35=4×243=9724 \times 3^5 = 4 \times 243 = 972 However, we must subtract the cases where Flag 6 matches Flag 1.

  6. Using the Inclusion-Exclusion Principle: If Flag 1 and Flag 6 are the same color, we effectively have a line of 5 flags to color with 4 choices for the first flag and 3 choices for each of the next four flags: 4×34=4×81=3244 \times 3^4 = 4 \times 81 = 324

  7. Final Calculation: Applying inclusion-exclusion, the total valid arrangements is: 972324=648972 - 324 = 648

However, upon reviewing the answer choices, this result does not match any of the options provided. This discrepancy suggests that we may need to double-check our solution approach or assumptions.

Based on standard combinatorial techniques and coloring restrictions, if a different solution method is expected, we might need to verify if simplifications are involved.


Would you like further clarification on any of the steps or another approach to the problem?

Related Questions:

  1. How does the circular arrangement affect the color choices compared to a linear arrangement?
  2. What are some common techniques for solving combinatorial coloring problems?
  3. Can the inclusion-exclusion principle be applied differently to achieve the correct answer?
  4. How would the answer change if additional colors were available?
  5. Are there formulas for circular arrangements in combinatorial problems?

Tip:

When working with circular arrangements in combinatorics, always account for the fact that the first and last items in the sequence are adjacent.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Combinatorics
Graph Theory
Circular Arrangement

Formulas

Total arrangements = 4 * 3^5 - 4 * 3^4

Theorems

Inclusion-Exclusion Principle

Suitable Grade Level

Grades 9-12