Math Problem Statement

Your college newspaper, The Collegiate Investigator, has fixed production costs of $74 per edition and marginal printing and distribution costs of 41¢ per copy. The Collegiate Investigator sells for 51¢ per copy. (a) Write down the associated cost function C(x) in dollars. C(x) =

Write down the revenue function R(x) in dollars. R(x) =

Write down the profit function P(x) in dollars. P(x) =

(b) What profit (or loss) results from the sale of 500 copies of The Collegiate Investigator? $ (c) How many copies should be sold in order to break even? copies

Solution

Let's break down the given problem step by step.

(a) Cost, Revenue, and Profit Functions

1. Cost Function C(x)C(x):

  • The fixed cost is $74 per edition.
  • The marginal (per copy) cost is 41¢ (which is $0.41) per copy. Thus, the total cost function C(x)C(x) in dollars (where xx is the number of copies) is: C(x)=74+0.41xC(x) = 74 + 0.41x

2. Revenue Function R(x)R(x):

  • The selling price per copy is 51¢ (which is $0.51). Thus, the revenue function R(x)R(x) in dollars is: R(x)=0.51xR(x) = 0.51x

3. Profit Function P(x)P(x):

  • Profit is the difference between revenue and cost. Thus, the profit function P(x)P(x) is: P(x)=R(x)C(x)=0.51x(74+0.41x)P(x) = R(x) - C(x) = 0.51x - (74 + 0.41x) Simplifying: P(x)=0.51x740.41x=0.10x74P(x) = 0.51x - 74 - 0.41x = 0.10x - 74

(b) Profit (or Loss) from the Sale of 500 Copies

We can calculate the profit when x=500x = 500 copies are sold by substituting x=500x = 500 into the profit function: P(500)=0.10(500)74=5074=24P(500) = 0.10(500) - 74 = 50 - 74 = -24 Thus, the newspaper incurs a loss of $24 when 500 copies are sold.

(c) Break-even Point

At the break-even point, profit equals zero. So, we set the profit function P(x)=0P(x) = 0 and solve for xx: 0.10x74=00.10x - 74 = 0 0.10x=740.10x = 74 x=740.10=740x = \frac{74}{0.10} = 740 Thus, 740 copies need to be sold to break even.


Summary of answers:

(a)
Cost function: C(x)=74+0.41xC(x) = 74 + 0.41x
Revenue function: R(x)=0.51xR(x) = 0.51x
Profit function: P(x)=0.10x74P(x) = 0.10x - 74

(b) Profit (or loss) from 500 copies: $-24 (loss)

(c) Break-even point: 740 copies


Would you like a more detailed explanation on any part of this? Here are some related questions:

  1. What happens to profit if the price per copy changes?
  2. How would fixed costs affect the break-even point?
  3. How does an increase in sales volume impact overall profit?
  4. What if the marginal cost per copy increased to 45¢?
  5. How is break-even analysis useful for businesses?

Tip: When calculating profits, always ensure to subtract all costs, including both fixed and variable, from your total revenue!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Functions
Profit and Loss Analysis

Formulas

Cost function: C(x) = 74 + 0.41x
Revenue function: R(x) = 0.51x
Profit function: P(x) = 0.10x - 74

Theorems

Linear cost and revenue models
Break-even analysis

Suitable Grade Level

Grades 9-12