Math Problem Statement

2 Calculate the coefficient of variation for the data: [5, 10, 15, 20, 25].

Solution

To calculate the coefficient of variation (CV) for the data set [5,10,15,20,25][5, 10, 15, 20, 25], we need the following steps:

Step 1: Calculate the Mean

The mean (μ\mu) is the average of the data set.

μ=5+10+15+20+255=755=15\mu = \frac{5 + 10 + 15 + 20 + 25}{5} = \frac{75}{5} = 15

Step 2: Calculate the Standard Deviation

The standard deviation (σ\sigma) measures the spread of the data. We can calculate it using the formula:

σ=(xiμ)2N\sigma = \sqrt{\frac{\sum (x_i - \mu)^2}{N}}

Where:

  • xix_i are the individual data points,
  • μ\mu is the mean,
  • NN is the number of data points.

For the given data:

For x1=5,(x1μ)2=(515)2=(10)2=100\text{For } x_1 = 5, (x_1 - \mu)^2 = (5 - 15)^2 = (-10)^2 = 100 For x2=10,(x2μ)2=(1015)2=(5)2=25\text{For } x_2 = 10, (x_2 - \mu)^2 = (10 - 15)^2 = (-5)^2 = 25 For x3=15,(x3μ)2=(1515)2=02=0\text{For } x_3 = 15, (x_3 - \mu)^2 = (15 - 15)^2 = 0^2 = 0 For x4=20,(x4μ)2=(2015)2=52=25\text{For } x_4 = 20, (x_4 - \mu)^2 = (20 - 15)^2 = 5^2 = 25 For x5=25,(x5μ)2=(2515)2=102=100\text{For } x_5 = 25, (x_5 - \mu)^2 = (25 - 15)^2 = 10^2 = 100

Sum of squared deviations: 100+25+0+25+100=250100 + 25 + 0 + 25 + 100 = 250

Now, divide by the number of data points N=5N = 5:

2505=50\frac{250}{5} = 50

Take the square root to find the standard deviation:

σ=507.071\sigma = \sqrt{50} \approx 7.071

Step 3: Calculate the Coefficient of Variation

The coefficient of variation is the ratio of the standard deviation to the mean, expressed as a percentage:

CV=σμ×100=7.07115×10047.05%CV = \frac{\sigma}{\mu} \times 100 = \frac{7.071}{15} \times 100 \approx 47.05\%

Final Answer:

The coefficient of variation for the data set [5,10,15,20,25][5, 10, 15, 20, 25] is approximately 47.05%.


Would you like more details on any of the steps, or do you have further questions?

Here are some related questions:

  1. How does the coefficient of variation help in comparing different data sets?
  2. What happens to the coefficient of variation if the mean of a data set increases?
  3. How do you interpret a high coefficient of variation in a data set?
  4. How can you calculate the standard deviation for a sample instead of a population?
  5. What other measures of dispersion are used alongside standard deviation and coefficient of variation?

Tip: The coefficient of variation is especially useful for comparing the relative variability between datasets with different units or scales!

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Math Problem Analysis

Mathematical Concepts

Statistics
Measures of Dispersion
Coefficient of Variation
Mean
Standard Deviation

Formulas

Mean: μ = (Σx_i) / N
Standard Deviation: σ = sqrt(Σ(x_i - μ)^2 / N)
Coefficient of Variation: CV = (σ / μ) * 100

Theorems

Formula for Coefficient of Variation
Formula for Standard Deviation

Suitable Grade Level

Grades 9-12