Math Problem Statement

Four functions are given. Decide whether each is an even function, an odd function, or neither.

Solution

Let's analyze the given functions to determine whether each is even, odd, or neither:

1. The function rr (top-left graph):

  • Observation: The graph of rr does not exhibit symmetry around either the y-axis (required for an even function) or the origin (required for an odd function).
  • Conclusion: The function rr is neither even nor odd.

2. The function ss (top-right graph):

  • Observation: The graph of ss is symmetric about the y-axis, meaning that for every xx, s(x)=s(x)s(-x) = s(x).
  • Conclusion: The function ss is even.

3. The function g(x)=6x5+7x3g(x) = -6x^5 + 7x^3 (bottom-left equation):

  • Observation: All powers of xx in the function are odd, which suggests that g(x)=g(x)g(-x) = -g(x).
  • Conclusion: The function g(x)g(x) is odd.

4. The function h(x)=6x5+3x2h(x) = -6x^5 + 3x^2 (bottom-right equation):

  • Observation: The function contains both odd (5th degree) and even (2nd degree) powers of xx, which suggests that h(x)h(x) does not satisfy the conditions for being either even or odd.
  • Conclusion: The function h(x)h(x) is neither even nor odd.

Would you like any further details or explanations?

Here are 5 related questions to further explore this topic:

  1. What is the mathematical definition of an even function?
  2. What conditions must be met for a function to be classified as odd?
  3. How can you algebraically verify whether a function is even, odd, or neither?
  4. Why does symmetry about the y-axis correspond to an even function?
  5. Can a function be both even and odd?

Tip: For functions defined explicitly, like g(x)g(x) or h(x)h(x), you can check their parity by substituting x-x for xx and simplifying.

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Math Problem Analysis

Mathematical Concepts

Function Symmetry
Even and Odd Functions

Formulas

f(-x) = f(x) for even
f(-x) = -f(x) for odd

Theorems

Symmetry with respect to y-axis (Even)
Symmetry with respect to origin (Odd)

Suitable Grade Level

Grades 10-12