Math Problem Statement
A highway patrolman records the following speeds (in mph) for 25 cars that pass through his radar within a five-minute interval: 52 57 51 55 49 60 59 55 45 53 46 57 62 61 60 50 50 48 65 58 57 52 48 46 51 You are to construct a histogram for this data set consisting of the classes 44 - 49, 50-55, 56-61, and 62-67. What will be the width of each class? Select the correct response: 5.0 6.0 5.5 4.5
Solution
To determine the width of each class in the histogram, we need to examine the range of values for each class.
The classes given are:
- 44 - 49
- 50 - 55
- 56 - 61
- 62 - 67
The width of a class is simply the difference between the upper and lower bounds of the class. Let's calculate the width for each of the classes:
-
44 - 49:
Upper bound = 49, Lower bound = 44
Width = 49 - 44 = 5.0 -
50 - 55:
Upper bound = 55, Lower bound = 50
Width = 55 - 50 = 5.0 -
56 - 61:
Upper bound = 61, Lower bound = 56
Width = 61 - 56 = 5.0 -
62 - 67:
Upper bound = 67, Lower bound = 62
Width = 67 - 62 = 5.0
Since each class has the same width of 5, the correct answer is:
5.0
Would you like to see how to create the histogram or have any questions about this?
Related questions:
- How do you calculate the frequency of each class in a histogram?
- What is the difference between a histogram and a bar chart?
- How would you calculate the mean and median from this data set?
- Why is the class width an important factor in constructing a histogram?
- How do you choose appropriate class intervals for a histogram?
Tip:
For consistency in histograms, it's important to ensure that all class widths are equal and that the class intervals cover the full range of the data without overlap.
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Math Problem Analysis
Mathematical Concepts
Statistics
Data Analysis
Histogram Construction
Formulas
Class Width = Upper Bound - Lower Bound
Theorems
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Suitable Grade Level
Grades 8-10