Math Problem Statement

A highway patrolman records the following speeds (in mph) for 25 cars that pass through his radar within a five-minute interval: 52 57 51 55 49 60 59 55 45 53 46 57 62 61 60 50 50 48 65 58 57 52 48 46 51 You are to construct a histogram for this data set consisting of the classes 44 - 49, 50-55, 56-61, and 62-67. What will be the width of each class? Select the correct response: 5.0 6.0 5.5 4.5

Solution

To determine the width of each class in the histogram, we need to examine the range of values for each class.

The classes given are:

  • 44 - 49
  • 50 - 55
  • 56 - 61
  • 62 - 67

The width of a class is simply the difference between the upper and lower bounds of the class. Let's calculate the width for each of the classes:

  1. 44 - 49:
    Upper bound = 49, Lower bound = 44
    Width = 49 - 44 = 5.0

  2. 50 - 55:
    Upper bound = 55, Lower bound = 50
    Width = 55 - 50 = 5.0

  3. 56 - 61:
    Upper bound = 61, Lower bound = 56
    Width = 61 - 56 = 5.0

  4. 62 - 67:
    Upper bound = 67, Lower bound = 62
    Width = 67 - 62 = 5.0

Since each class has the same width of 5, the correct answer is:

5.0

Would you like to see how to create the histogram or have any questions about this?

Related questions:

  1. How do you calculate the frequency of each class in a histogram?
  2. What is the difference between a histogram and a bar chart?
  3. How would you calculate the mean and median from this data set?
  4. Why is the class width an important factor in constructing a histogram?
  5. How do you choose appropriate class intervals for a histogram?

Tip:

For consistency in histograms, it's important to ensure that all class widths are equal and that the class intervals cover the full range of the data without overlap.

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Math Problem Analysis

Mathematical Concepts

Statistics
Data Analysis
Histogram Construction

Formulas

Class Width = Upper Bound - Lower Bound

Theorems

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Suitable Grade Level

Grades 8-10