Math Problem Statement
Solution
In the given circuit (Fig. 3-39), we are tasked with calculating the current and the power absorbed by the dependent source. Here’s a breakdown of the key steps to solve this:
Step 1: Analyzing the Circuit Components
- There is a 16 A current source connected in parallel with:
- A 14 Ω resistor,
- A current-dependent current source (which depends on the current through the 70 Ω resistor),
- A 70 Ω resistor where the current is .
Step 2: Apply Kirchhoff's Current Law (KCL) at the Node
Since the 16 A current splits between the 14 Ω resistor, the dependent current source (with a gain of 2), and the 70 Ω resistor, KCL at the node gives: Where:
- is the current through the 14 Ω resistor,
- is the current through the 70 Ω resistor, and
- is the current provided by the dependent source.
Step 3: Express the Voltage in Terms of
The voltage across the 70 Ω resistor is: Substitute this into the equation for the current through the 14 Ω resistor: Simplify: Solving for :
Step 4: Calculate Power Absorbed by the Dependent Source
The dependent current source provides . The voltage across it is the same as across the 70 Ω resistor, which is .
Thus, the power absorbed by the dependent source is:
Final Answers:
- The current ,
- The power absorbed by the dependent source is .
Would you like more details on any of these steps?
Here are some related questions you can explore:
- How would the circuit change if the dependent source was voltage-dependent?
- What would happen if the 70 Ω resistor was removed from the circuit?
- How do dependent current sources behave in different circuit configurations?
- How is power dissipation calculated for passive and active circuit elements?
- How does Kirchhoff's Current Law apply in complex circuits with multiple nodes?
Tip: When solving circuit problems, always verify if the dependent source is current- or voltage-dependent to apply the correct relationships!
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Math Problem Analysis
Mathematical Concepts
Circuit Analysis
Ohm's Law
Kirchhoff's Current Law (KCL)
Power Calculation
Formulas
Kirchhoff's Current Law (KCL): ΣI = 0 at a node
Ohm's Law: V = IR
Power: P = VI
Theorems
Kirchhoff's Current Law (KCL)
Ohm's Law
Suitable Grade Level
Undergraduate Electrical Engineering
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