Math Problem Statement

Solve the questions from the textbook page shown in the image.

Solution

Let's go through each question in the image step-by-step.


Question 1

Identify the elements of the circle shown.

From the diagram:

  • OO: Center of the circle
  • A,B,C,D,E,FA, B, C, D, E, F: Points on the circle's circumference
  • ABAB: Diameter (line passing through the center OO)
  • FGFG: Radius (half the diameter)
  • OCOC: Radius
  • GG: A point on the radius, possibly where the radius meets a chord or segment.

The main elements in a circle include:

  • Center
  • Radius
  • Diameter
  • Circumference
  • Chord (a line segment with endpoints on the circle)

Question 2

A wheel rotates 1000 times to cover a distance of 1320 meters. Find the radius of the wheel.

  1. Calculate the circumference (CC) of the wheel: C=1320meters1000=1.32metersC = \frac{1320 \, \text{meters}}{1000} = 1.32 \, \text{meters}

  2. Use the circumference formula, C=2πrC = 2 \pi r, to find the radius rr: 1.32=2πr1.32 = 2 \pi r r=1.322π0.21meters21cmr = \frac{1.32}{2 \pi} \approx 0.21 \, \text{meters} \approx 21 \, \text{cm}


Question 3

Calculate the perimeter of each given shape.

Part (a)

A shape with two semi-circles on either side of a rectangle:

  • Rectangle length = 16 cm, width = 14 cm
  • Radius of each semi-circle = 142=7\frac{14}{2} = 7 cm
  1. Calculate the circumference of each semi-circle (half of 2πr2 \pi r): Perimeter of one semi-circle=π×7=7π21.99cm\text{Perimeter of one semi-circle} = \pi \times 7 = 7\pi \approx 21.99 \, \text{cm}

  2. Add the two semi-circle perimeters and the two lengths of the rectangle: Total Perimeter=2×16+2×7π32+43.98=75.98cm\text{Total Perimeter} = 2 \times 16 + 2 \times 7\pi \approx 32 + 43.98 = 75.98 \, \text{cm}

Part (b)

A quarter circle:

  • Radius = 21 cm
  1. Perimeter includes one-quarter of the circumference plus the two radii: Quarter circle perimeter=14×2π×21+2×21\text{Quarter circle perimeter} = \frac{1}{4} \times 2 \pi \times 21 + 2 \times 21 =π×212+4232.99+42=74.99cm= \frac{\pi \times 21}{2} + 42 \approx 32.99 + 42 = 74.99 \, \text{cm}

Question 4

The area of a circle is given as 28.26cm228.26 \, \text{cm}^2. Find the diameter.

  1. Use the area formula, A=πr2A = \pi r^2: 28.26=πr228.26 = \pi r^2 r2=28.26π9r^2 = \frac{28.26}{\pi} \approx 9 r=3cmr = 3 \, \text{cm}

  2. The diameter d=2r=6cmd = 2r = 6 \, \text{cm}.


Question 5

A circular garden has a diameter of 28 meters. If the cost to plant grass is Rp 6,000 per square meter, calculate the total cost.

  1. Find the area of the garden: Radius=282=14m\text{Radius} = \frac{28}{2} = 14 \, \text{m} Area=π×142=196π615.75m2\text{Area} = \pi \times 14^2 = 196\pi \approx 615.75 \, \text{m}^2

  2. Calculate the total cost: Total Cost=615.75×6000=3,694,500Rp\text{Total Cost} = 615.75 \times 6000 = 3,694,500 \, \text{Rp}


Would you like further details on any of these answers? Here are five related questions:

  1. How do you calculate the circumference of a circle with different values for radius?
  2. Can the formula for area be used to solve problems involving arcs or sectors?
  3. How would the cost change if the radius of the garden were doubled?
  4. What happens to the diameter if the area of the circle doubles?
  5. How would you calculate the perimeter of an irregular shape that includes arcs and straight edges?

Tip: Remember that understanding the basic formulas for circles (like area and circumference) makes it easier to handle complex shapes that include arcs or semi-circles.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Circle Properties
Perimeter
Area
Circumference

Formulas

Circumference of a circle: C = 2πr
Area of a circle: A = πr^2
Perimeter of a semi-circle: P = πr
Perimeter of a quarter-circle: P = (πr / 2) + 2r

Theorems

Properties of circles and segments

Suitable Grade Level

Grade 9