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The problem asks to approximate the circumference \( C \) and area \( A \) of a circle with radius \( r = 1 \, \text{cm} \), using \( \pi \approx \frac{22}{7} \).

### 1. **Circumference**:
The formula for the circumference of a circle is:
\[
C = 2 \pi r
\]
Substitute \( \pi \approx \frac{22}{7} \) and \( r = 1 \, \text{cm} \):
\[
C \approx 2 \times \frac{22}{7} \times 1 = \frac{44}{7} \, \text{cm}
\]
So, the circumference \( C \approx \frac{44}{7} \, \text{cm} \).

### 2. **Area**:
The formula for the area of a circle is:
\[
A = \pi r^2
\]
Substitute \( \pi \approx \frac{22}{7} \) and \( r = 1 \, \text{cm} \):
\[
A \approx \frac{22}{7} \times 1^2 = \frac{22}{7} \, \text{cm}^2
\]
So, the area \( A \approx \frac{22}{7} \, \text{cm}^2 \).

### Final answers:
- \( C \approx \frac{44}{7} \, \text{cm} \)
- \( A \approx \frac{22}{7} \, \text{cm}^2 \)

Let me know if you want any further clarification or details.

Here are 5 related questions:
1. How would the circumference and area change if the radius was doubled?
2. What would the exact circumference be if \( \pi \) was used instead of \( \frac{22}{7} \)?
3. How does the approximation of \( \frac{22}{7} \) for \( \pi \) affect the precision of the area and circumference?
4. Can the radius be a fraction? If so, how would the formulas be adjusted?
5. What is the relationship between the diameter and the circumference of a circle?

**Tip**: Always keep track of units, especially when dealing with area and circumference.

A circle has radius 1 cm. Use π ≈ 22/7 to approximate its circumference and area. Enter the answers as reduced fractions.

Calculate the circumference and area of a circle with a radius of 1 cm using π ≈ 22/7. This problem demonstrates how to apply basic geometry formulas for circumference and area. Suitable for students in Grades 6-8.

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