Math Problem Statement

A circle has radius 1 cm. Use π ≈ 22/7 to approximate its circumference and area. Enter the answers as reduced fractions.

Solution

The problem asks to approximate the circumference CC and area AA of a circle with radius r=1cmr = 1 \, \text{cm}, using π227\pi \approx \frac{22}{7}.

1. Circumference:

The formula for the circumference of a circle is: C=2πrC = 2 \pi r Substitute π227\pi \approx \frac{22}{7} and r=1cmr = 1 \, \text{cm}: C2×227×1=447cmC \approx 2 \times \frac{22}{7} \times 1 = \frac{44}{7} \, \text{cm} So, the circumference C447cmC \approx \frac{44}{7} \, \text{cm}.

2. Area:

The formula for the area of a circle is: A=πr2A = \pi r^2 Substitute π227\pi \approx \frac{22}{7} and r=1cmr = 1 \, \text{cm}: A227×12=227cm2A \approx \frac{22}{7} \times 1^2 = \frac{22}{7} \, \text{cm}^2 So, the area A227cm2A \approx \frac{22}{7} \, \text{cm}^2.

Final answers:

  • C447cmC \approx \frac{44}{7} \, \text{cm}
  • A227cm2A \approx \frac{22}{7} \, \text{cm}^2

Let me know if you want any further clarification or details.

Here are 5 related questions:

  1. How would the circumference and area change if the radius was doubled?
  2. What would the exact circumference be if π\pi was used instead of 227\frac{22}{7}?
  3. How does the approximation of 227\frac{22}{7} for π\pi affect the precision of the area and circumference?
  4. Can the radius be a fraction? If so, how would the formulas be adjusted?
  5. What is the relationship between the diameter and the circumference of a circle?

Tip: Always keep track of units, especially when dealing with area and circumference.

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Math Problem Analysis

Mathematical Concepts

Geometry
Circle Properties

Formulas

Circumference of a circle: C = 2πr
Area of a circle: A = πr²

Theorems

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Suitable Grade Level

Grades 6-8