Math Problem Statement
During the school holidays, Chris read 312 pages of a book at first. He read the remaining pages in 20 days, with the some number of pages each day. During these 20 days, he read 1/12 of the book in 6 days. How many pages did he read in the 6 days?
Solution
Let the total number of pages in the book be denoted by . Chris initially read 312 pages, so the remaining pages are . These remaining pages were read over 20 days, with the same number of pages each day.
Let represent the number of pages Chris read per day during the 20 days. Then, the total number of pages read in 20 days is:
We are also told that Chris read of the book in the first 6 days of the 20-day period. The number of pages read in these 6 days is , and this is equal to of the total pages :
To solve this, first express in terms of using the second equation:
Now, substitute this value of into the first equation:
Simplifying:
To eliminate the fraction, multiply through by 18:
Distribute the 18 on the right-hand side:
Now, move all terms involving to one side:
Solve for :
Thus, the total number of pages in the book is . Now, to find how many pages Chris read in the 6 days, use the formula for :
Therefore, in 6 days, Chris read:
Final Answer:
Chris read 36 pages in 6 days.
Would you like further clarification or details on any part of the solution?
Here are 5 questions to deepen your understanding:
- How would the result change if Chris had read the same number of pages in 10 days instead of 6?
- What is the total number of pages Chris read in 20 days?
- How can we calculate the number of pages left after Chris read for the first 6 days?
- How can you generalize this method for any book with a different number of pages?
- How would the calculations change if Chris read of the book in the first 6 days?
Tip: When solving word problems, always identify and define all the variables before setting up equations. This helps organize your approach and avoid confusion.
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Math Problem Analysis
Mathematical Concepts
Algebra
Proportions
Linear Equations
Formulas
p * 20 = T - 312
6p = 1/12 * T
p = T / 72
Theorems
-
Suitable Grade Level
Grades 6-8
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