Math Problem Statement

A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per liter. In order to reduce the concentration of chlorine, fresh water is pumped into the tank at a rate of 16 L/s. The mixture is kept stirred and is pumped out at a rate of 40 L/s. Find the amount of chlorine in the tank as a function of time. (Let y be the amount of chlorine in grams and t be the time in seconds.)

Solution

We are given a tank with an initial chlorine concentration of 0.0125 g/L in 1600 L of water. Fresh water is pumped into the tank at a rate of 16 L/s, and the mixture is pumped out at a rate of 40 L/s. The mixture is well-stirred, so the concentration of chlorine in the tank is uniform at all times.

We are tasked with finding the amount of chlorine y(t)y(t) in grams as a function of time tt in seconds.

Step 1: Setting up the differential equation

Let:

  • y(t)y(t) represent the amount of chlorine (in grams) in the tank at time tt,
  • The volume of water decreases at a rate of 4016=24L/s40 - 16 = 24 \, \text{L/s}, so after tt seconds, the volume in

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Rate of Change
Mixture Problems

Formulas

dy/dt = - (rate of outflow) * (concentration of chlorine)

Theorems

Separation of Variables
Exponential Decay in First-Order Differential Equations

Suitable Grade Level

Undergraduate Level (First-Year Calculus)