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This problem describes a situation where Chloe spends £400 on petrol this year, and each year her spending decreases by 25%. Let's break this down:

- **Initial spending** this year: £400.
- **Next year**, the spending decreases by 25%, so she will spend 75% of this year's amount (since 100% - 25% = 75%).

We can calculate the spending for the next year and the year after.

### a) **Next year**:
Chloe will spend 75% of £400.
\[
\text{Next year's spending} = 400 \times 0.75 = 300
\]
So, Chloe will spend **£300** next year.

### b) **The year after next**:
For the year after next, Chloe's spending will again decrease by 25%, so she will spend 75% of £300 (next year's spending):
\[
\text{Year after next's spending} = 300 \times 0.75 = 225
\]
So, Chloe will spend **£225** the year after next.

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Would you like further details or clarifications on any part of this solution?

### Related Questions:
1. What would Chloe spend in the third year after next if the 25% decrease continues?
2. How much total would Chloe spend in the next two years combined?
3. Can you express Chloe’s spending in year \(n\) using a formula?
4. How long will it take for Chloe’s spending to drop below £100?
5. How much has Chloe saved by spending less each year compared to if she spent £400 every year?

### Tip:
In problems involving repeated percentage decreases, think of each new amount as a percentage (like 75%) of the previous one to quickly find future values.

Chloe spent £400 on petrol this year. Each year the amount she spends on petrol decreases by 25%. How much will she spend on petrol next year? The year after next?

Discover how much Chloe will spend on petrol next year and the year after, given that her spending decreases by 25% each year. This problem involves percentage decrease and exponential decay, suitable for students in Grades 6-8.

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