Math Problem Statement

A random sample of 130 students enrolled in statistics units in recent semesters at Macquarie University has been selected to study use of practice quizzes and academic performance. Some of the variables recorded for each student are listed below.

Variable Description subid Subject ID intDom domestic or international numQuizzes the number of practice quizzes attempted unitMark the final unit mark ageGroupCat the age of students

Part 1

Research question: We wish to investigate whether the age of students enrolled in statistics units in recent semesters at Macquarie University is distributed according to the table below. the age of students | 1 (less than 19) | 2 (19-21) | 3 (22-24) | 4 (more than 24) Percentage | 10 | 40 | 30 | 20 Please complete the following table calculating the values of A, B and C.

           | 1 (less than 19) | 2 (19-21) | 3 (22-24) | 4 (more than 24) | Total 

Observed Count | A=*** | 37 | 36 | 23 | 130
Expected Count | 13 | 52 | B=*** | 26 | 130
chi squared | 33.923 | 4.327 | 0.231 | C=*** | 38.827 A [integer]: B [use at least 3dp]:

Solution

To complete this table, we need to calculate the missing values AA, BB, and CC. Here's the approach:

Step 1: Determine Observed Count AA

The total observed count for all categories is 130. Since counts for categories 2, 3, and 4 are given (37, 36, and 23 respectively), we can find AA by subtracting these from the total:

A=130(37+36+23)=13096=34A = 130 - (37 + 36 + 23) = 130 - 96 = 34

Step 2: Determine Expected Count BB

The expected counts are calculated based on the percentages given for each age group. For category 3 (22-24), the expected count BB is based on 30% of the total sample of 130 students:

B=0.30×130=39B = 0.30 \times 130 = 39

Step 3: Determine Chi-Squared Value CC

The chi-squared statistic for each category is calculated as:

χ2=(OE)2E\chi^2 = \frac{(O - E)^2}{E}

where OO is the observed count, and EE is the expected count. To find CC, which is the chi-squared value for the fourth category:

C=(2326)226=926=0.346C = \frac{(23 - 26)^2}{26} = \frac{9}{26} = 0.346

Summary of Values

  1. A (Observed Count for category 1): A=34A = 34
  2. B (Expected Count for category 3): B=39.000B = 39.000
  3. C (Chi-squared for category 4): C=0.346C = 0.346

Would you like more detailed explanations on chi-squared calculations?


Further Questions to Explore:

  1. What does the chi-squared value represent in this context?
  2. How does changing sample size affect the chi-squared value?
  3. Why is the expected count derived from percentage distributions?
  4. How would the result change if observed counts differed slightly?
  5. What conclusion could be drawn from a high total chi-squared value?

Tip:

When calculating expected counts, always ensure they are proportional to the sample size and distribution percentages.

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Math Problem Analysis

Mathematical Concepts

Statistics
Chi-Squared Test
Expected Value Calculation
Proportions

Formulas

Expected Count = (Percentage / 100) * Total Sample Size
Chi-Squared Formula: χ² = (O - E)^2 / E

Theorems

Chi-Squared Goodness-of-Fit Test

Suitable Grade Level

College Level