Math Problem Statement

A leading CEO mentoring organization offers a program for chief​ executives, presidents, and business owners with a focus on developing entrepreneurial skills. Women and men executives that recently completed the program rated its value and the results are given in the accompanying table​ (marked Original​ Data). The​ chi-square procedures are not appropriate for the Original Data table because the expected counts are too small. ​ However, by changing the​ table, an analysis can still be performed. We can often proceed after combining cells in some way that makes sense and also produce a table in which the conditions are satisfied. Both accompanying tables display the same​ data, but the second combines​ "Marginal" and​ "Poor" into a new category called​ "Below Average". Are the perceptions of the​ program's value the same for men and​ women? Complete parts a through c below.

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Part 1

​a) Find the expected counts for each cell in the new table​ (Combined Data​ table).

​(Round to two decimal places as​ needed.)

MenMen

WomenWomen

Excellent

enter your response here

enter your response here

Above Average

enter your response here

enter your response here

Average

enter your response here

enter your response here

Below AverageBelow Average

enter your response here

enter your response here

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Data table

Original Data

MenMen

WomenWomen   Excellent

33

1010

Above Average

99

1212

Average

1515

88

Marginal

77

22

Poor

33

11

Combined Data

MenMen

WomenWomen   Excellent

33

1010

Above Average

99

1212

Average

1515

88

Below Average

1010

33

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Solution

To calculate the expected counts for the Combined Data table, we use the formula for expected frequency in a contingency table:

E=(RowTotal)×(ColumnTotal)GrandTotalE = \frac{(Row \, Total) \times (Column \, Total)}{Grand \, Total}

Step 1: Extract the totals

From the Combined Data table:

CategoryMenWomenRow Totals
Excellent331043
Above Average91221
Average15823
Below Average10313
Column Totals6733100

Step 2: Compute expected counts

Using the formula E=(RowTotal)×(ColumnTotal)GrandTotalE = \frac{(Row \, Total) \times (Column \, Total)}{Grand \, Total}, we compute the expected count for each cell.

Excellent:

  • Men: 43×67100=28.81\frac{43 \times 67}{100} = 28.81
  • Women: 43×33100=14.19\frac{43 \times 33}{100} = 14.19

Above Average:

  • Men: 21×67100=14.07\frac{21 \times 67}{100} = 14.07
  • Women: 21×33100=6.93\frac{21 \times 33}{100} = 6.93

Average:

  • Men: 23×67100=15.41\frac{23 \times 67}{100} = 15.41
  • Women: 23×33100=7.59\frac{23 \times 33}{100} = 7.59

Below Average:

  • Men: 13×67100=8.71\frac{13 \times 67}{100} = 8.71
  • Women: 13×33100=4.29\frac{13 \times 33}{100} = 4.29

Step 3: Organize the results in a table

CategoryMen (Expected)Women (Expected)
Excellent28.8114.19
Above Average14.076.93
Average15.417.59
Below Average8.714.29

Let me know if you want help calculating the χ2\chi^2 statistic or interpreting the results! Here are some follow-up questions and a tip:


Follow-Up Questions:

  1. What is the formula to compute the χ2\chi^2 statistic?
  2. How do you interpret the degrees of freedom in this scenario?
  3. What conditions must be met for the χ2\chi^2 test to be valid?
  4. How would combining categories affect the statistical power of this test?
  5. What are the implications if the null hypothesis is rejected?

Tip:

Always ensure that each expected cell count is greater than 5 to meet the assumptions of the χ2\chi^2 test.

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Math Problem Analysis

Mathematical Concepts

Chi-Square Test of Independence
Contingency Tables
Expected Frequency Calculation

Formulas

Expected frequency formula: E = (Row Total × Column Total) / Grand Total
Chi-Square statistic formula: χ² = Σ((Observed - Expected)² / Expected)

Theorems

Chi-Square Test Assumptions

Suitable Grade Level

Undergraduate Statistics or Advanced High School Statistics