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It appears you’re working on a chemistry assignment involving calculations related to moles, atoms, and molar masses. Let’s tackle the questions shown in the image:

1. **Problem 001**: *How many atoms of aluminum (Al) are in 6.4 mol of aluminum?*

   - Use Avogadro's number to solve this: \(6.022 \times 10^{23}\) atoms/mol.
   - Calculation: \(6.4 \text{ mol} \times 6.022 \times 10^{23} \approx 3.85408 \times 10^{24} \) atoms.
   - The answer that matches closely is **option 6**: \(3.85 \times 10^{24}\).

2. **Problem 002**: *What is the mass of 1.305 mol of chlorine (Cl)?*

   - Chlorine’s atomic mass is approximately 35.45 g/mol.
   - Calculation: \(1.305 \text{ mol} \times 35.45 \text{ g/mol} \approx 46.26225\) g.
   - The closest answer is **option 8**: \(46.2623\) g.

3. **Problem 003**: *How much oxygen (O) is in 3.96 x \(10^{4}\) atoms of oxygen?*

   - Convert atoms to moles, then to grams.
   - Calculation: \( \frac{3.96 \times 10^4}{6.022 \times 10^{23}} \approx 6.57789 \times 10^{-19} \) mol.
   - The answer that matches closely is **option 5**: \(6.57789 \times 10^{-19}\) g.

4. **Problem 004**: *Find the molar mass of \((CH_3)_2NH\).*

   - Calculate the molar mass based on atomic masses: \(C = 12.01\), \(H = 1.008\), \(N = 14.01\).
   - Calculation: \( (2 \times 12.01) + (7 \times 1.008) + (1 \times 14.01) = 45.094\) g/mol.
   - The answer that matches closely is **option 1**: \(45.087\) g/mol.

If you’d like detailed explanations on the steps involved or assistance with additional questions, feel free to ask!

Here are some further questions to deepen your understanding:

1. How does Avogadro’s number help in converting moles to atoms or molecules?
2. Why is it important to use atomic masses precisely in mole calculations?
3. What are the implications of rounding off in chemistry calculations?
4. How do you calculate the molar mass of a compound with multiple elements?
5. Can you identify when to use molar mass versus atomic mass in different types of problems?

**Tip:** Always keep track of units in your calculations to avoid mistakes in conversions!

How many atoms of aluminum (Al) are in 6.4 mol of aluminum? What is the mass of 1.305 mol of chlorine (Cl)? How much oxygen (O) is in 3.96 x 10^4 atoms of oxygen? Find the molar mass of (CH3)2NH.

Explore mole calculations for aluminum, chlorine, and oxygen atoms, along with finding the molar mass of (CH3)2NH. This problem set involves Avogadro's number and basic chemistry formulas for calculating atoms and mass in moles, suitable for high school students in Grades 10-12.

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