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The problem provided involves calculating the centripetal force on an object in circular motion. The formula for centripetal force is:

\[
F = \frac{mv^2}{r}
\]

Where:
- \( m \) is the mass of the object (in kilograms),
- \( v \) is the tangential velocity (in meters per second),
- \( r \) is the radius of the circular path (in meters).

### Given Data:
- Mass (\( m \)) = 2 kg,
- Tangential velocity (\( v \)) = 50 cm/s = 0.50 m/s (converted to meters per second),
- Radius (\( r \)) = 25 cm = 0.25 m (converted to meters).

Now, let's plug the values into the formula and calculate the centripetal force.

\[
F = \frac{(2 \, \text{kg}) \times (0.50 \, \text{m/s})^2}{0.25 \, \text{m}}
\]

\[
F = \frac{2 \times 0.25}{0.25}
\]

\[
F = \frac{0.5}{0.25} = 2 \, \text{N}
\]

### The centripetal force is 2 Newtons (N).

Would you like more details on this calculation or have any questions?

Here are some related questions:
1. How does increasing the velocity affect centripetal force?
2. What happens to the centripetal force if the radius of the circular path is halved?
3. Can centripetal force be negative? Why or why not?
4. How does mass influence the magnitude of centripetal force in circular motion?
5. What is the role of friction in maintaining circular motion for real-world objects?

**Tip:** Always make sure to convert all units to the SI system (meters, seconds, kilograms) when calculating physical quantities.

What is the centripetal force of a 2-kg object traveling at 50 cm/s in a circular path with a radius of 25 centimeters?

Calculate the centripetal force on a 2-kg object moving at 50 cm/s in a circular path with a radius of 25 cm. Learn the step-by-step solution using the formula F = (mv^2)/r. Suitable for high school physics students.

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