Math Problem Statement

Identify the center and radius to graph a circle given its equation 2x^2 - 10x + 2y^2 - 8y = -5/2.

Solution

The equation shown in the image is:

2x210x+2y28y=522x^2 - 10x + 2y^2 - 8y = -\frac{5}{2}

This represents the equation of a circle, but it needs to be rewritten in standard form to determine the center and radius. Here's the step-by-step process:

Step 1: Group xx and yy terms

Group the xx-terms and the yy-terms together, like this:

2(x25x)+2(y24y)=522(x^2 - 5x) + 2(y^2 - 4y) = -\frac{5}{2}

Step 2: Factor out the 2

Factor out the 2 from both groups:

2[(x25x)+(y24y)]=522[(x^2 - 5x) + (y^2 - 4y)] = -\frac{5}{2}

Next, we want the equation in the form where we can complete the square inside both parentheses.

Step 3: Complete the square

To complete the square for x25xx^2 - 5x, take half of 5-5, square it, and add it inside the parentheses:

  • Half of 5-5 is 52-\frac{5}{2}, and its square is 254\frac{25}{4}.

For y24yy^2 - 4y, take half of 4-4, square it, and add it inside the parentheses:

  • Half of 4-4 is 2-2, and its square is 44.

Add 254\frac{25}{4} and 44 to both sides to balance the equation:

2[(x52)2+(y2)2]=52+2×(254+4)2[(x - \frac{5}{2})^2 + (y - 2)^2] = -\frac{5}{2} + 2 \times \left( \frac{25}{4} + 4 \right)

Step 4: Simplify the equation

Now simplify the right side. First, compute the values inside the parentheses:

254+4=254+164=414\frac{25}{4} + 4 = \frac{25}{4} + \frac{16}{4} = \frac{41}{4}

So,

52+2×414=52+412=362=18- \frac{5}{2} + 2 \times \frac{41}{4} = - \frac{5}{2} + \frac{41}{2} = \frac{36}{2} = 18

Thus, the equation becomes:

2[(x52)2+(y2)2]=182[(x - \frac{5}{2})^2 + (y - 2)^2] = 18

Step 5: Divide by 2

Divide both sides by 2:

(x52)2+(y2)2=9(x - \frac{5}{2})^2 + (y - 2)^2 = 9

Step 6: Identify the center and radius

This is now in the standard form of a circle equation:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

Where (h,k)(h, k) is the center and rr is the radius. From the equation:

  • The center is (52,2)\left(\frac{5}{2}, 2\right).
  • The radius is r=3r = 3 (since r2=9r^2 = 9).

So, the center is (2.5,2)(2.5, 2) as shown in the image, and the radius should be 3.

Let me know if you'd like further details on any step!

5 Related Questions:

  1. How do you complete the square for quadratic terms in general?
  2. How do you graph a circle given its center and radius?
  3. How do you determine the equation of a circle from a graph?
  4. What is the importance of standard form for circles?
  5. How do transformations affect the position of a circle on a coordinate plane?

Tip:

When completing the square, remember to balance the equation by adding the same value to both sides.

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Math Problem Analysis

Mathematical Concepts

Geometry
Algebra
Completing the Square
Equations of Circles

Formulas

(x - h)^2 + (y - k)^2 = r^2
Standard form of a circle equation
Completing the square formula

Theorems

The equation of a circle is in the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.

Suitable Grade Level

Grades 9-12