Math Problem Statement

If A = {5, 6, 7}, B = {7, 8}, and C = {5, 8}, then find (i) (A × B) ∩ (A × C) and (ii) (A ∪ B ∪ C)'.

Solution

Let's solve the problem given in the image.

Problem

Given sets:

  • A={5,6,7}A = \{5, 6, 7\}
  • B={7,8}B = \{7, 8\}
  • C={5,8}C = \{5, 8\}

Find:

  1. (A×B)(A×C)(A \times B) \cap (A \times C)
  2. (ABC)(A \cup B \cup C)' (assuming the complement is taken with respect to the universal set, which we’ll assume later)

Solution

Part (i) (A×B)(A×C)(A \times B) \cap (A \times C)

  1. Find A×BA \times B: This is the Cartesian product of sets AA and BB, which includes all ordered pairs where the first element is from AA and the second element is from BB. A×B={(5,7),(5,8),(6,7),(6,8),(7,7),(7,8)}A \times B = \{ (5,7), (5,8), (6,7), (6,8), (7,7), (7,8) \}

  2. Find A×CA \times C: Similarly, the Cartesian product of sets AA and CC. A×C={(5,5),(5,8),(6,5),(6,8),(7,5),(7,8)}A \times C = \{ (5,5), (5,8), (6,5), (6,8), (7,5), (7,8) \}

  3. Intersection (A×B)(A×C)(A \times B) \cap (A \times C): We find common elements in A×BA \times B and A×CA \times C. (A×B)(A×C)={(5,8),(6,8),(7,8)}(A \times B) \cap (A \times C) = \{ (5,8), (6,8), (7,8) \}

So, the answer for part (i) is: (A×B)(A×C)={(5,8),(6,8),(7,8)}(A \times B) \cap (A \times C) = \{ (5,8), (6,8), (7,8) \}

Part (ii) (ABC)(A \cup B \cup C)'

To find the complement (ABC)(A \cup B \cup C)', we first need to determine ABCA \cup B \cup C.

  1. Union ABCA \cup B \cup C: ABC={5,6,7,8}A \cup B \cup C = \{5, 6, 7, 8\}

  2. Complement (ABC)(A \cup B \cup C)': To find the complement, we need to assume a universal set. If no universal set is given, we can't determine this directly. However, if we assume the universal set UU includes elements that are naturally within the range of numbers 1 to, say, 10, then: U={1,2,3,4,5,6,7,8,9,10}U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\} Then the complement is: (ABC)=U(ABC)={1,2,3,4,9,10}(A \cup B \cup C)' = U - (A \cup B \cup C) = \{1, 2, 3, 4, 9, 10\}

Thus, the answer for part (ii), assuming U={1,2,3,4,5,6,7,8,9,10}U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}, is: (ABC)={1,2,3,4,9,10}(A \cup B \cup C)' = \{1, 2, 3, 4, 9, 10\}

Would you like further details or have any specific questions?

Related Questions:

  1. How would the answer change if the universal set UU had different elements?
  2. Can you explain how to find the Cartesian product of two sets?
  3. What are some properties of set complements?
  4. How does the intersection of Cartesian products differ from the union of Cartesian products?
  5. How is the concept of set complement useful in probability?

Tip:

When dealing with sets and Cartesian products, always start by clearly defining each set operation step by step to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Cartesian Product
Set Union
Set Intersection
Set Complement

Formulas

Cartesian Product: A × B = {(a, b) | a ∈ A, b ∈ B}
Set Union: A ∪ B = {x | x ∈ A or x ∈ B}
Set Intersection: A ∩ B = {x | x ∈ A and x ∈ B}
Set Complement: A' = U - A (where U is the universal set)

Theorems

Commutative property of union: A ∪ B = B ∪ A
Distributive property of intersection over union

Suitable Grade Level

Grades 9-12