Math Problem Statement

For some species, if the number of individuals falls below a certain critical number, the population faces extinction (since it is no longer capable of avoiding damaging effects of inbreeding and is unable to cope with changes in the environment).

Suppose that for a population of southern mountain caribou in British Columbia, this critical number is 572.

Suppose that in 1991 there were 5071 southern mountain caribou in British Columbia, and in 2024 only 2626 remain. Assume that the per capita production rate r is constant and that time t is measured in years.

(a) Determine the per capita production rate r. (b) After how many years will the caribou population first fall to the level that will threaten their survival?

Solution

To address this problem, we can model the population growth of the southern mountain caribou using the exponential growth model, which assumes that the per capita production rate, rr, remains constant over time.

Exponential Growth Model:

The general equation for exponential growth is:

P(t)=P0ertP(t) = P_0 e^{rt}

Where:

  • P(t)P(t) is the population at time tt.
  • P0P_0 is the initial population at time t=0t = 0.
  • rr is the per capita growth rate.
  • tt is the time in years.

Given Data:

  • In 1991, the population was P0=5071P_0 = 5071.
  • In 2024, the population was P(2024)=2626P(2024) = 2626.
  • The critical population for survival is 572, which is the threshold we need to calculate when the population will reach this number.

We need to solve for rr first and then determine when the population will fall to 572.

Part (a): Determining the per capita production rate rr

We can use the formula for exponential growth and plug in the known values:

P(2024)=P0er(20241991)P(2024) = P_0 e^{r \cdot (2024 - 1991)}

2626=5071er332626 = 5071 e^{r \cdot 33}

Now solve for rr:

26265071=e33r\frac{2626}{5071} = e^{33r}

0.5177=e33r0.5177 = e^{33r}

Taking the natural logarithm (ln) of both sides:

ln(0.5177)=33r\ln(0.5177) = 33r

0.6594=33r-0.6594 = 33r

r=0.6594330.01997(per year)r = \frac{-0.6594}{33} \approx -0.01997 \quad \text{(per year)}

Thus, the per capita production rate is approximately r=0.01997r = -0.01997 per year.

Part (b): Time when population reaches the critical threshold

To find when the population reaches the critical level of 572, we can use the same exponential growth equation. We need to find tt such that P(t)=572P(t) = 572.

572=5071ert572 = 5071 e^{r \cdot t}

Substitute r0.01997r \approx -0.01997:

572=5071e0.01997t572 = 5071 e^{-0.01997 \cdot t}

Solve for tt:

5725071=e0.01997t\frac{572}{5071} = e^{-0.01997 \cdot t}

0.1128=e0.01997t0.1128 = e^{-0.01997 \cdot t}

Take the natural logarithm of both sides:

ln(0.1128)=0.01997t\ln(0.1128) = -0.01997 \cdot t

2.1787=0.01997t-2.1787 = -0.01997 \cdot t

Solve for tt:

t=2.17870.01997109.1(years)t = \frac{-2.1787}{-0.01997} \approx 109.1 \quad \text{(years)}

Since t=0t = 0 corresponds to 1991, we add 109.1 years to 1991:

1991+109.121001991 + 109.1 \approx 2100

Thus, the caribou population will first fall to the critical level of 572 around the year 2100.

Final Answers:

(a) The per capita production rate rr is approximately 0.01997-0.01997 per year.

(b) The population will first fall to the critical level of 572 after approximately 109 years, or in the year 2100.


Would you like any further explanation or clarification on any step? Here are some additional questions to explore:

  1. How would the model change if the per capita production rate was positive instead of negative?
  2. What factors could affect the actual survival of the caribou in the real world, even with a model like this?
  3. How can a population model be adapted to include the effects of inbreeding or environmental changes?
  4. What are some methods for estimating the per capita production rate from real-world data?
  5. If the caribou population were to experience a sudden increase in population size, how would the model need to be adjusted?

Tip: Always double-check the units of your time and population to ensure consistency when using growth models.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth and Decay
Logarithms
Population Modeling

Formulas

P(t) = P0 * e^(rt)
ln(x) = log base e of x

Theorems

Properties of Exponents and Logarithms

Suitable Grade Level

Grades 10-12