The band sponsored a car wash. During the first session, the students earned $78. During the afternoon session, they earned $54. That evening when people were on their way home from work, the students earned $81. If the band charged a whole dollar amount for each car, what was the charge per car?

To determine the charge per car, we can assume that the same price was charged for each car at all sessions. 

Let $ x $ be the charge per car. The total number of cars washed would then be equal to the total earnings divided by the price per car.

### Total earnings:
\[
78 \, \text{(morning session)} + 54 \, \text{(afternoon session)} + 81 \, \text{(evening session)} = 213 \, \text{dollars}
\]

Now, we need to determine a whole dollar amount $ x $ that divides 213 evenly, meaning that $ 213 \div x $ must be a whole number. We can find the divisors of 213.

### Divisors of 213:
\[
213 = 3 \times 71
\]
So the divisors of 213 are: $ 1, 3, 71, 213 $.

Since the charge per car is a whole dollar amount, we will try reasonable values of $ x $:
- $ x = 3 $, this gives:
  \[
  213 \div 3 = 71
  \]

Thus, the charge per car is likely **$3**.

Would you like more details or have any questions?

### Related Questions:
1. How many cars were washed during each session?
2. If the price per car had been $4, what would have been the total earnings?
3. How would the total earnings change if they washed 10 more cars during the afternoon session?
4. What percentage of the total earnings came from the evening session?
5. If the band decided to increase the price to $5 per car, how many cars would they need to wash to make $300?

**Tip**: Always check if a number divides evenly when trying to find the price per item in such problems!

Find out how to calculate the charge per car when students earned $78 in the morning, $54 in the afternoon, and $81 in the evening from a car wash. This problem demonstrates basic arithmetic and divisibility rules, suitable for students in Grades 5-7.

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