Math Problem Statement

Devoir surveillé: Analyse 1 with exercises on limits, trigonometric identities, and function properties.

Solution

This is an analysis (calculus) exercise set with three main parts, covering topics such as limits, trigonometric identities, and properties of functions, including continuity, differentiability, and domain analysis. Here’s a structured breakdown of each exercise:

Exercise 1: Limits

  1. Calculate the limits:
    • 1=limx+x52x+1x6+2x+4+x\ell_1 = \lim_{x \to +\infty} \frac{x^5 - 2x + 1}{x^6 + 2x + 4 + x}
    • 2=limx+cos(x)x3\ell_2 = \lim_{x \to +\infty} \frac{\cos(x)}{x^3}
    • 3=limx0sh(x)x\ell_3 = \lim_{x \to 0} \frac{\operatorname{sh}(x)}{x}
    • 4=limx+(1+1x)x\ell_4 = \lim_{x \to +\infty} \left(1 + \frac{1}{x}\right)^x

Each of these limits requires different techniques, including asymptotic analysis, L'Hôpital's Rule, or recognizing standard limit forms.

Exercise 2: Trigonometric and Inverse Trigonometric Identities

  1. Show that x[1,1]\forall x \in [-1, 1]: arccos(x)+arcsin(x)=π2\arccos(x) + \arcsin(x) = \frac{\pi}{2}.
    • This result uses the relationship between the arccosine and arcsine functions.
  2. Simplify expressions involving inverse trigonometric functions:
    • (a) A=arcsin(sin(24π5))A = \arcsin\left(\sin\left(\frac{24\pi}{5}\right)\right)
    • (b) B=arccos(sin(24π5))B = \arccos\left(\sin\left(\frac{24\pi}{5}\right)\right)
    • (c) C=arccos(cos(24π5))C = \arccos\left(\cos\left(\frac{24\pi}{5}\right)\right)
    • (d) D=arcsin(cos(24π5))D = \arcsin\left(\cos\left(\frac{24\pi}{5}\right)\right)

This part involves finding equivalent expressions for each function using periodicity and the ranges of inverse trigonometric functions.

Exercise 3: Function Analysis

  1. Consider functions ff and gg defined by:
    • f(x)=arctan(x)+arctan(1x)f(x) = \arctan(x) + \arctan\left(\frac{1}{x}\right)

    • g(x)=arcsin(x)f(x)g(x) = \arcsin(x) f(x)

    • (a) Determine the domain of definition for ff.

    • (b) Determine the domain of differentiability for ff and calculate ff'.

    • (c) Show that f(x)={π2if x>0π2if x<0f(x) = \begin{cases} \frac{\pi}{2} & \text{if } x > 0 \\ -\frac{\pi}{2} & \text{if } x < 0 \end{cases}.

    • (d) Find the domain of definition for gg.

    • (e) Show that gg can be extended continuously at x=0x = 0. Denote this extension as hh.

    • (f) Calculate limx0arcsin(x)x\lim_{x \to 0} \frac{\arcsin(x)}{x}.

    • (g) Show that hh is not differentiable at x=0x = 0.

This part involves understanding limits, continuity, differentiability, and the behavior of trigonometric functions around singularities.

Would you like a step-by-step solution for any of these exercises?

Here are related questions to help deepen understanding:

  1. What are common methods for evaluating limits that approach infinity?
  2. How can we use trigonometric identities to simplify expressions with inverse trigonometric functions?
  3. How does continuity at a point differ from differentiability at that point?
  4. What role does the range of inverse trigonometric functions play in simplifying expressions?
  5. How can periodicity of trigonometric functions be applied to evaluate inverse trigonometric values?

Tip: When calculating limits, always check if you can simplify the expression before applying complex techniques like L'Hôpital's Rule.

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Math Problem Analysis

Mathematical Concepts

Calculus
Limits
Inverse Trigonometric Functions
Continuity
Differentiability

Formulas

Limit definitions and properties
L'Hôpital's Rule
Inverse trigonometric identities: arccos(x) + arcsin(x) = π/2

Theorems

Fundamental Theorem of Calculus
Properties of Inverse Trigonometric Functions

Suitable Grade Level

Undergraduate level (Calculus 1 or Introductory Analysis)