The given expression is calculating the wavelength ($\lambda_{\text{AM}}$) of an AM radio wave using the formula:

$\lambda_{\text{AM}} = \frac{c}{f}$

Where:

• $c = 3.0 \times 10^8 \, \text{m/s}$ is the speed of light in a vacuum.
• $f = 1.230 \times 10^6 \, \text{Hz}$ is the frequency of the radio wave.

To compute the wavelength:

$\lambda_{\text{AM}} = \frac{3.0 \times 10^8}{1.230 \times 10^6}$

Let's perform the calculation:

1. Divide the numbers: $\frac{3.0 \times 10^8}{1.230 \times 10^6} = \frac{3.0}{1.230} \times 10^{8-6} = 2.439 \times 10^2$

2. Simplifying the powers of ten: $2.439 \times 10^2 = 243.9 \, \text{m}$

Thus, the wavelength $\lambda_{\text{AM}}$ is approximately 243.9 meters, as shown in the image.

Would you like more details on this calculation or related topics?

Related Questions:

1. How does frequency affect wavelength in electromagnetic waves?
2. What is the speed of light, and why is it used in these calculations?
3. How do you convert frequencies from MHz to Hz for similar problems?
4. What is the significance of AM and FM in radio frequencies?
5. How do wavelength and frequency relate in other types of waves, like sound waves?

Tip:

Always ensure that units are consistent when calculating. Here, frequency was given in $\text{Hz}$ (1 Hz = 1 cycle per second), while the speed of light is in meters per second (m/s).