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To solve this, we need to determine the unit rate (or speed) for both horses and then identify which one is faster.

### Given:
- **Horse A**: The equation \( y = 580x \) describes the distance \( y \) (in meters) that Horse A can cover in \( x \) minutes. This equation shows that Horse A has a constant speed of 580 meters per minute.
  
- **Horse B**: We can find Horse B's unit rate by examining the graph and identifying how much distance it covers in a given time.

### Solution:
1. **Determine the rate of Horse B**:
   - From the graph, at \( x = 2 \) minutes, \( y = 1100 \) meters.
   - Speed (rate) of Horse B = \(\frac{\text{Distance}}{\text{Time}} = \frac{1100 \text{ meters}}{2 \text{ minutes}} = 550 \text{ meters per minute}\).

2. **Compare the rates**:
   - Horse A's speed = 580 meters per minute.
   - Horse B's speed = 550 meters per minute.

Since 580 meters per minute (Horse A) is greater than 550 meters per minute (Horse B), **Horse A** is the faster horse.

### Answer:
The correct answer is **580 meters per minute**.

Would you like further details on this problem?

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Here are five related questions to expand on this information:

1. How can you calculate the unit rate if you only have the equation and not a graph?
2. What does the slope of the line on a distance-time graph represent?
3. How would the graph change if Horse B's speed increased to match Horse A’s?
4. Why is it important to compare unit rates in real-world problems?
5. How can you determine the faster rate if both horses had different time intervals?

**Tip:** Always remember that the unit rate in distance-time graphs is the slope of the line, representing speed in meters per minute or other distance/time units.

The distance y in meters that can be covered by Horse A in x minutes can be represented by the equation y = 580x. The distance that can be covered by Horse B is shown on the graph. Determine the unit rate of the faster horse.

Learn how to determine the unit rate of the faster horse by comparing distances covered in a given time. This problem involves linear equations, slope interpretation, and calculating unit rates, suitable for Grades 6-8.

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