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The problem states that the cost of tuition varies directly with the number of credit hours. This means the relationship between the total cost and the number of credit hours can be modeled by a linear equation of the form:

\[
\text{Cost} = k \times \text{Credit Hours}
\]

where $k$ is the constant of proportionality.

Given:
- For 11 credit hours, the total cost is $880.

We can solve for $k$ by using this information:
\[
880 = k \times 11
\]
\[
k = \frac{880}{11} = 80
\]

Now that we know the constant $k = 80$, we can find the total cost for 19 credit hours:
\[
\text{Cost for 19 credit hours} = 80 \times 19 = 1520
\]

So, the total cost for 19 credit hours is **$1520**.

Would you like more details, or do you have any questions?

Here are 5 related questions for deeper understanding:
1. What would be the cost for 15 credit hours using the same rate?
2. How would the equation change if the tuition included a fixed fee in addition to the per-credit charge?
3. Can this method be used if the cost varied by different ranges of credit hours?
4. If a student took 30 credit hours in a year, what would be the total tuition cost?
5. How does varying tuition costs impact a student taking more or fewer credit hours?

**Tip:** In direct variation problems, once the proportionality constant is determined, you can use it to find values for any amount within the given conditions.

What is the total cost of 19 credit hours, if the cost of 11 credit hours is $880?

Learn how to calculate the total cost of 19 credit hours using direct variation, where the cost of 11 credit hours is $880. This algebraic problem involves calculating a proportional constant and applying it to find the desired cost. Suitable for students in Grades 8-10.

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