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berapa gaya yang di dapat kan pada benda 5kg

To solve for the force (tension \( T_2 \)) acting on the 5 kg object, let's analyze the system given:

1. **Given Information:**
   - Masses: \( m_1 = 2 \, \text{kg} \), \( m_2 = 3 \, \text{kg} \), \( m_3 = 5 \, \text{kg} \).
   - Applied Force: \( F = 30 \, \text{N} \) on the entire system.
   - The surface is frictionless.

2. **Total Mass of the System:**
   \[
   M_{\text{total}} = m_1 + m_2 + m_3 = 2 + 3 + 5 = 10 \, \text{kg}
   \]

3. **Acceleration of the System:**
   Using Newton's Second Law for the whole system:
   \[
   F = M_{\text{total}} \times a \Rightarrow a = \frac{F}{M_{\text{total}}} = \frac{30}{10} = 3 \, \text{m/s}^2
   \]

4. **Force on the 5 kg Mass (Tension \( T_2 \)):**
   To find the force on the 5 kg object, \( T_2 \), we use the acceleration:
   \[
   T_2 = m_3 \times a = 5 \times 3 = 15 \, \text{N}
   \]

### Answer:
The force (tension \( T_2 \)) acting on the 5 kg object is **15 N**.

Would you like a detailed breakdown of each step, or do you have any questions?

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Here are 5 related questions to further explore this topic:
1. What is the tension \( T_1 \) between the 2 kg and 3 kg masses?
2. How would the tensions \( T_1 \) and \( T_2 \) change if there was friction on the surface?
3. What would happen to the acceleration if an additional force was applied in the opposite direction?
4. How is the net force distributed across each object in this system?
5. How would this setup change if the force was applied to the 2 kg block instead of the 5 kg block?

**Tip:** Always check the direction of the applied force and any frictional forces when analyzing such problems; it can affect tension values.

Learn how to calculate the force (tension) on a 5 kg object in a system where multiple masses are connected by a string on a frictionless surface, with an applied force of 30 N. This problem covers key physics concepts including Newton's Second Law and the dynamics of a system. Suitable for high school physics students.

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