Math Problem Statement

A worksheet with problems on calculating sides and angles of right triangles and isosceles triangles, involving Pythagorean theorem and trigonometric properties.

Solution

Let's work through each question on your worksheet systematically.

Problem Breakdown and Solutions:

  1. Calculate the hypotenuse of a right triangle (Question 1):

    • Use the Pythagorean theorem: c=a2+b2c = \sqrt{a^2 + b^2}.
    • For each triangle:
      • (a) a=7 cm,b=24 cma = 7 \text{ cm}, b = 24 \text{ cm} c=72+242=49+576=625=25 cmc = \sqrt{7^2 + 24^2} = \sqrt{49 + 576} = \sqrt{625} = 25 \text{ cm}
      • (b) a=3.2 cm,b=2.4 cma = 3.2 \text{ cm}, b = 2.4 \text{ cm} c=3.22+2.42=10.24+5.76=16=4 cmc = \sqrt{3.2^2 + 2.4^2} = \sqrt{10.24 + 5.76} = \sqrt{16} = 4 \text{ cm}
  2. Calculate the unknown leg of a right triangle (Question 2):

    • Again, use the Pythagorean theorem, but solve for the missing leg: b=c2a2b = \sqrt{c^2 - a^2}
    • For each triangle:
      • (a) c=20 cm,a=12 cmc = 20 \text{ cm}, a = 12 \text{ cm} b=202122=400144=256=16 cmb = \sqrt{20^2 - 12^2} = \sqrt{400 - 144} = \sqrt{256} = 16 \text{ cm}
      • (b) c=8 cm,a=4.5 cmc = 8 \text{ cm}, a = 4.5 \text{ cm} b=824.52=6420.25=43.756.61 cmb = \sqrt{8^2 - 4.5^2} = \sqrt{64 - 20.25} = \sqrt{43.75} \approx 6.61 \text{ cm}
  3. Determine if a triangle is a right triangle based on side lengths (Question 3):

    • Check if the triangle satisfies a2+b2=c2a^2 + b^2 = c^2.
      • (a) 14 cm,48 cm,50 cm14 \text{ cm}, 48 \text{ cm}, 50 \text{ cm}: 142+482=196+2304=2500and502=250014^2 + 48^2 = 196 + 2304 = 2500 \quad \text{and} \quad 50^2 = 2500 This is a right triangle.
      • (b) 32 cm,25.5 cm,25.7 cm32 \text{ cm}, 25.5 \text{ cm}, 25.7 \text{ cm}: 322+25.52=1024+650.25=1674.25but25.72=660.4932^2 + 25.5^2 = 1024 + 650.25 = 1674.25 \quad \text{but} \quad 25.7^2 = 660.49 This is not a right triangle.
  4. Calculate the length of the perpendicular leg in a right triangle based on a diagonal angle (Question 4):

    • Given AC=30 cmAC = 30 \text{ cm} and ABC=60\angle ABC = 60^\circ, find the leg opposite and adjacent to the angle.
    • Since it forms a 3030^\circ-6060^\circ-9090^\circ triangle, the ratio of sides is 1:3:21 : \sqrt{3} : 2.
      • The length of BC=AC2=302=15 cmBC = \frac{AC}{2} = \frac{30}{2} = 15 \text{ cm}.
      • The length of the other leg, AB=15325.98 cmAB = 15\sqrt{3} \approx 25.98 \text{ cm}.
  5. Find the angles in isosceles triangles using the given heights or angles (Question 5):

    • For each part, use the properties of isosceles triangles and supplementary angle properties.
    • (a) ADC=ABC=120\angle ADC = \angle ABC = 120^\circ.
    • (b) Use the given information to deduce remaining angles based on triangle properties.

Would you like further details on any specific question, or would you like assistance with similar problems?

Follow-up Questions:

  1. How would you solve for an unknown angle in a triangle if only two sides are given?
  2. How do you calculate the area of a right triangle given its two legs?
  3. Can you find the missing side of a triangle if only one side and one angle are known?
  4. How do the side ratios work in 30-60-90 triangles, and why do they hold?
  5. Can you use trigonometric functions (sin, cos, tan) to solve these triangles?

Tip:

Remember, in any right triangle, the Pythagorean theorem can help confirm side lengths, and trigonometric functions can help determine angles and other unknown sides if one side and one angle are known.

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Math Problem Analysis

Mathematical Concepts

Right triangles
Isosceles triangles
Trigonometry
Geometry

Formulas

Pythagorean theorem: c = √(a² + b²)
Missing leg formula: b = √(c² - a²)
30-60-90 triangle ratios: 1 : √3 : 2

Theorems

Pythagorean theorem
Properties of 30-60-90 triangles
Properties of isosceles triangles

Suitable Grade Level

Grades 8-10