To solve this, we need to calculate the total number of possible outcomes for each event (coin tosses, die rolls, and card draws) and then multiply them together.

1. Coin tosses: When a coin is tossed, there are 2 possible outcomes: heads (H) or tails (T). If the coin is tossed 4 times, the number of possible outcomes for the 4 tosses is: $2 \times 2 \times 2 \times 2 = 2^4 = 16$ So, there are 16 possible outcomes for the coin tosses.

2. Die rolls: A standard six-sided die has 6 possible outcomes for each roll (numbers 1 through 6). If the die is rolled 2 times, the number of possible outcomes for the 2 rolls is: $6 \times 6 = 6^2 = 36$ So, there are 36 possible outcomes for the die rolls.

3. Card draws: In a standard deck of 52 cards, two cards are drawn without replacement. The number of ways to choose 2 cards from 52 without replacement (order doesn’t matter) is given by the combination formula: $\binom{52}{2} = \frac{52 \times 51}{2} = 1326$ So, there are 1,326 possible outcomes for the card draws.

Total number of possible outcomes:

To find the total number of possible outcomes for all events (coin tosses, die rolls, and card draws), we multiply the individual outcomes together: $16 \times 36 \times 1326 = 763,776$

Thus, the total number of different possible outcomes is 763,776.

Would you like further details on any of the steps or have any other questions? Here are some related questions for you to explore:

1. What is the difference between combinations and permutations in probability?
2. How do you calculate the number of possible outcomes when there are multiple independent events?
3. What is the probability of getting at least one heads in 4 coin tosses?
4. How does the number of sides on a die affect the number of possible outcomes?
5. How do you calculate the probability of drawing two specific cards from a deck?

Tip: Remember that when events are independent (like coin tosses, die rolls, and card draws), the total number of outcomes is the product of the outcomes of each event.