Math Problem Statement

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Solution

Let's analyze and solve the equation provided in the image step-by-step.

The equation is: T=12πμCT = \frac{1}{2 \pi \sqrt{\mu C}} where μ\mu and CC are given values. Based on the second part of your equation, the specific values seem to be:

  • μ=9.3×103\mu = 9.3 \times 10^3
  • C=106C = 10^{-6}

Now, let’s substitute these values and calculate TT.

Step 1: Calculate the product inside the square root

μC=9.3×103×106=9.3×103\mu \cdot C = 9.3 \times 10^3 \times 10^{-6} = 9.3 \times 10^{-3}

Step 2: Take the square root

9.3×103=9.3×103\sqrt{9.3 \times 10^{-3}} = \sqrt{9.3} \times \sqrt{10^{-3}} 9.33.05,103=101.5=0.03162\sqrt{9.3} \approx 3.05, \quad \sqrt{10^{-3}} = 10^{-1.5} = 0.03162 9.3×103=3.05×0.031620.0965\sqrt{9.3 \times 10^{-3}} = 3.05 \times 0.03162 \approx 0.0965

Step 3: Calculate the denominator 2πμC2 \pi \sqrt{\mu C}

2π6.2832 \pi \approx 6.283 2πμC=6.283×0.09650.6062 \pi \sqrt{\mu C} = 6.283 \times 0.0965 \approx 0.606

Step 4: Compute the final value of TT

T=10.6061.65T = \frac{1}{0.606} \approx 1.65

Final Answer

T1.65T \approx 1.65

Let me know if you need any further details or have any other questions!


Here are five questions related to this problem:

  1. What physical quantity might this equation represent (e.g., period or frequency)?
  2. How does changing μ\mu or CC affect the result?
  3. What are the units of TT in this case?
  4. Can the product μC\mu C be interpreted physically?
  5. How does this result change if CC is doubled?

Tip: Always track units carefully in problems like this to avoid confusion!

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Math Problem Analysis

Mathematical Concepts

Physics
Oscillations
Square Root Calculation
Multiplication of Powers of 10

Formulas

T = 1 / (2 * π * √(μ * C))

Theorems

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Suitable Grade Level

Grades 10-12