Math Problem Statement
Solution
Let's solve each of the questions in the new image one by one.
Question 4
Bruce's Electronics sold 487 tablets last year at $384.99 each. This year their price decreased to $337.99 and units sold increased to 635.
a) What is the percent change in price year-over-year?
To calculate the percent change in price:
Given:
- Old Price = $384.99
- New Price = $337.99
So, the percent change in price is approximately .
b) What is the percent change in units sold year-over-year?
To calculate the percent change in units sold:
Given:
- Old Units Sold = 487
- New Units Sold = 635
So, the percent change in units sold is approximately .
c) What is the percent change in total revenue year-over-year?
First, calculate the total revenue for each year:
- Last year's revenue:
- This year's revenue:
To calculate the percent change in total revenue:
So, the percent change in total revenue is approximately .
Question 5
To find the number of years it would take for $8,000 to grow to $30,000 with an annual rate of change of 8.611786%:
We use the compound interest formula:
Given:
- is the number of years
Rearranging the formula to solve for :
Rounding to the nearest whole year, it would take approximately years for $8,000 to grow to $30,000 at an annual rate of change of 8.611786%.
Would you like any details or further explanation on any of these calculations?
Here are some more questions you might find interesting:
- How do you calculate the area under a curve using integration?
- What is the formula for calculating compound interest continuously?
- How do you solve quadratic inequalities?
- What is the significance of eigenvalues and eigenvectors in linear algebra?
- How do you find the standard deviation of a set of data?
Tip: When working with percentages, always remember to convert percentage rates to their decimal form before using them in calculations.
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Math Problem Analysis
Mathematical Concepts
Percent Change
Compound Interest
Formulas
Percent Change formula
Compound Interest formula
Theorems
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Suitable Grade Level
Advanced High School
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