To determine which statement is true, we need to calculate both the median and the mean of the number of books packed in the 10 boxes.

Step 1: Organize the data in ascending order:

6, 6, 9, 9, 10, 11, 12, 14, 15, 18

Step 2: Find the median:

Since there are 10 numbers (an even count), the median is the average of the 5th and 6th numbers in the ordered list.

• The 5th number is 10.
• The 6th number is 11.

To find the median: $\text{Median} = \frac{10 + 11}{2} = \frac{21}{2} = 10.5$

So, the median is 10.5, which is not 8 or 9.

Step 3: Find the mean:

The mean is the sum of all the numbers divided by the number of boxes. First, let's find the sum:

$6 + 6 + 9 + 9 + 10 + 11 + 12 + 14 + 15 + 18 = 100$

Now, divide by the number of boxes (10):

$\text{Mean} = \frac{100}{10} = 10$

So, the mean number of books to a box is 10, which is not 11 or 12.

Conclusion:

None of the options provided are correct, since:

• The median is 10.5 (not 8 or 9).
• The mean is 10 (not 11 or 12).

Would you like further clarification or additional questions? Here are a few related questions:

1. What is the effect of changing one of the numbers (e.g., increasing the 6 to a 20) on the median and mean?
2. How would the median change if there were an odd number of boxes?
3. How can you find the mean and median for data with a larger set of numbers?
4. How do the mean and median compare when the data set is skewed?
5. What is the mode of this data set?

Tip: Always organize your data before calculating the median or mean, especially for larger data sets!