The slide provides an overview of calculating density, defined as the mass per unit volume. The formula for density $D$ is given as:

$D = \frac{\text{mass (m)}}{\text{volume (V)}}$

In the sample problem, a 2.0 mL sample of oil with a mass of 1.76 g results in a density calculation as follows:

$D = \frac{1.76 \text{ g}}{2.0 \text{ mL}} = 0.88 \text{ g/mL}$

Now, let's solve the exercises provided:

1. Gasoline Density Calculation

   • Given: Volume $V = 15$ mL, Mass $m = 11$ g.
   • Calculation: $D_{\text{gasoline}} = \frac{11 \text{ g}}{15 \text{ mL}} = 0.73 \text{ g/mL}$

2. Glass Marble Density Calculation

   • Given: Volume $V = 2.5$ cm³, Mass $m = 7.5$ g.
   • Calculation: $D_{\text{glass marble}} = \frac{7.5 \text{ g}}{2.5 \text{ cm}^3} = 3 \text{ g/cm}^3$

3. Comparing Densities of Rubbing Alcohol and Wood

   • Rubbing Alcohol:
     • Given: Volume $V = 5.0$ mL, Mass $m = 4.0$ g.
     • Calculation: $D_{\text{rubbing alcohol}} = \frac{4.0 \text{ g}}{5.0 \text{ mL}} = 0.8 \text{ g/mL}$
   • Wood:
     • Given: Volume $V = 8.0 \text{ cm}^3$, Mass $m = 5.6$ g.
     • Calculation: $D_{\text{wood}} = \frac{5.6 \text{ g}}{8.0 \text{ cm}^3} = 0.7 \text{ g/cm}^3$
   • Conclusion: Rubbing alcohol has a higher density than wood.

Would you like more details on any of these solutions or have any questions?

Related Questions

1. What are the standard units for density in different substances?
2. How does temperature affect the density of substances?
3. Why is density an important property for identifying materials?
4. How can density be used to determine whether an object will float or sink?
5. What are some real-world applications where density is a crucial factor?

Tip: Remember, density can be used to identify unknown substances by comparing their calculated density to known values.