Math Problem Statement

before about 1970, most American homes owned a "phonograph" Or record-player" designed to reproduce music and speech from large plastic disk-shaped "records" (these were the "analog" precursors of the digital "compact discs" popular in the 1990s). These records would be placed on a motor-driven "turntable" that could be set to rotate at one or more of three speeds: 33, 45, or 78 revolutions per minute (rpm). The music was represented by variations in the size and shape of a continuous spiral "groove," starting near the outer rim of the record. A needle, attached to a metal arm pivoting from the side of the turntable, transmitted these variations to an electromechanical device that recreated the original sound. Some of the important features of rotational motion could be easily observed by watching the record go around HOW great an angle (in radians and in degrees) is covered by a spot on a 78-rpm record in 5 min of constant rotation? What are the linear speeds of two points, respectively 3 and 12 cm from the center of rotation? What are the corresponding angular speeds?

Solution

Let's break this problem into parts and solve each question step-by-step.

1. Angular displacement in radians and degrees (78 rpm for 5 minutes):

  • Revolutions per minute (rpm): 78rpm78 \, \text{rpm}
  • Time: 5minutes=5×60=300seconds5 \, \text{minutes} = 5 \times 60 = 300 \, \text{seconds}
  • Number of revolutions: Revolutions=78rev/min×5min=390revolutions\text{Revolutions} = 78 \, \text{rev/min} \times 5 \, \text{min} = 390 \, \text{revolutions}
  • Angular displacement in radians: Since one revolution equals 2πradians2\pi \, \text{radians}: θ=390rev×2πradians/rev=780πradians\theta = 390 \, \text{rev} \times 2\pi \, \text{radians/rev} = 780\pi \, \text{radians} θ2450.44radians\theta \approx 2450.44 \, \text{radians}
  • Angular displacement in degrees: Since one revolution equals 360360^\circ: θ=390rev×360/rev=140400\theta = 390 \, \text{rev} \times 360^\circ/\text{rev} = 140400^\circ

Answer:

  • Angular displacement: 780πradians780\pi \, \text{radians} or approximately 2450.44radians2450.44 \, \text{radians}, and 140400140400^\circ.

2. Linear speeds of points 3 cm and 12 cm from the center:

The linear speed (vv) is related to angular speed (ω\omega) and radius (rr) by the formula: v=rωv = r \omega

  • Angular speed (ω\omega): Convert 78rpm78 \, \text{rpm} to radians per second: ω=78rev/min×2πradians/rev60seconds/min=156π608.168radians/second\omega = 78 \, \text{rev/min} \times \frac{2\pi \, \text{radians/rev}}{60 \, \text{seconds/min}} = \frac{156\pi}{60} \approx 8.168 \, \text{radians/second}

  • Linear speed for r=3cmr = 3 \, \text{cm}: v=3cm×8.168radians/second24.504cm/secondv = 3 \, \text{cm} \times 8.168 \, \text{radians/second} \approx 24.504 \, \text{cm/second}

  • Linear speed for r=12cmr = 12 \, \text{cm}: v=12cm×8.168radians/second98.016cm/secondv = 12 \, \text{cm} \times 8.168 \, \text{radians/second} \approx 98.016 \, \text{cm/second}

Answer:

  • Linear speed at 3cm3 \, \text{cm}: 24.504cm/s24.504 \, \text{cm/s}
  • Linear speed at 12cm12 \, \text{cm}: 98.016cm/s98.016 \, \text{cm/s}

3. Corresponding angular speeds:

Angular speed (ω\omega) is the same for all points on the record, as it rotates as a rigid body.

Answer:

  • Angular speed: ω=8.168radians/second\omega = 8.168 \, \text{radians/second}

Summary of Results:

  1. Angular displacement: 780πradians780\pi \, \text{radians} or approximately 2450.44radians2450.44 \, \text{radians}, 140400140400^\circ.
  2. Linear speeds:
    • At 3cm3 \, \text{cm}: 24.504cm/s24.504 \, \text{cm/s}
    • At 12cm12 \, \text{cm}: 98.016cm/s98.016 \, \text{cm/s}
  3. Angular speed: 8.168radians/second8.168 \, \text{radians/second}.

Follow-up Questions:

  1. What would be the angular displacement for 10 minutes of rotation at 33 rpm?
  2. How does the linear speed change if the radius is doubled?
  3. If the record rotates at 45 rpm instead of 78 rpm, what are the new linear speeds for the same radii?
  4. How is the angular speed affected if the rotational speed changes from 78 rpm to 33 rpm?
  5. What is the relationship between linear speed and radius for a point on a rotating object?

Tip: Always check units when converting between angular and linear quantities to ensure consistency.

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Math Problem Analysis

Mathematical Concepts

Angular displacement
Linear speed
Angular speed
Rotational motion

Formulas

Angular displacement (radians) = 2π × revolutions
Angular speed (ω) = 2π × rpm / 60
Linear speed (v) = radius × angular speed (ω)

Theorems

Relationship between angular and linear velocity

Suitable Grade Level

Grades 10-12