Math Problem Statement

object a and object b both speed up during a 10 second time interval. object a increases in velocity 10m/s north while object B increases in velocity 5m/s east

Solution

In this scenario, both objects A and B experience a change in velocity during the same time interval, but their velocity changes in different directions:

  • Object A increases its velocity by 10 m/s north.
  • Object B increases its velocity by 5 m/s east.

Key Concepts:

  1. Velocity is a vector, meaning it has both magnitude and direction.
  2. The change in velocity (Δv) over time is known as acceleration. Acceleration is also a vector and is calculated by dividing the change in velocity by the time interval.

Let's calculate the acceleration of each object:

  • Object A's acceleration: aA=ΔvAt=10m/s10s=1m/s2northa_A = \frac{\Delta v_A}{t} = \frac{10 \, \text{m/s}}{10 \, \text{s}} = 1 \, \text{m/s}^2 \, \text{north}

  • Object B's acceleration: aB=ΔvBt=5m/s10s=0.5m/s2easta_B = \frac{\Delta v_B}{t} = \frac{5 \, \text{m/s}}{10 \, \text{s}} = 0.5 \, \text{m/s}^2 \, \text{east}

These accelerations are in different directions, so they cannot be directly compared without using vector addition. If we wanted to calculate the resultant acceleration of both objects combined (assuming we treat them as a single system), we would add these vectors.

Resultant acceleration:

The magnitude of the resultant acceleration aresultanta_{\text{resultant}} can be found using the Pythagorean theorem since the accelerations are perpendicular (north and east).

aresultant=(aA)2+(aB)2=(12+0.52)=1+0.25=1.251.12m/s2a_{\text{resultant}} = \sqrt{(a_A)^2 + (a_B)^2} = \sqrt{(1^2 + 0.5^2)} = \sqrt{1 + 0.25} = \sqrt{1.25} \approx 1.12 \, \text{m/s}^2

The direction of the resultant acceleration can be found using trigonometry (tan inverse of the ratio of the accelerations).

Do you want to see details of how to find the direction, or any clarifications?

Related Questions:

  1. What is the difference between speed and velocity?
  2. How do you add vector quantities in physics?
  3. How does acceleration relate to Newton's second law of motion?
  4. Can an object have zero velocity and still be accelerating?
  5. How would the analysis change if the two accelerations were in the same direction?

Tip:

Always remember that velocity and acceleration are vector quantities, which means they must include both magnitude and direction for complete description.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Kinematics
Vector Addition
Acceleration

Formulas

a_A = Δv_A / t = 1 m/s² north
a_B = Δv_B / t = 0.5 m/s² east
Resultant acceleration: a_resultant = √(a_A^2 + a_B^2)

Theorems

Pythagorean Theorem for perpendicular vectors
Trigonometry for vector angles

Suitable Grade Level

Grades 9-12