The reservoir can only be filled with 95% of water. Calculate the amount of water inside the reservoir. Give your answer to the nearest m³

The reservoir can be filled with only 95% of its total volume. Since the total volume of the reservoir is 14,797.5 m³, we calculate 95% of this volume as follows:

\[
\text{Amount of water} = 0.95 \times 14,797.5
\]

Let's calculate this:

\[
\text{Amount of water} = 14,057.625 \, \text{m}^3
\]

Rounding to the nearest cubic meter:

\[
\text{Amount of water} \approx 14,058 \, \text{m}^3
\]

So, the amount of water the reservoir can hold is **14,058 cubic meters (m³)**.

Would you like more details or have any questions?

Here are 5 related questions:
1. What percentage of the tank is empty when it is filled to 95%?
2. How much more water would be needed to fill the reservoir to its full capacity?
3. How many liters of water does 14,058 m³ correspond to?
4. If the height of the tank was increased by 5 meters, how much water could it hold at 95% capacity?
5. How much water is required to fill the reservoir up to 80%?

**Tip:** When working with percentages of volumes, ensure that you multiply the total volume by the decimal equivalent of the percentage.

Learn how to calculate the volume of water in a reservoir filled to 95% of its capacity. Given a total reservoir volume of 14,797.5 m³, find out how much water it can hold at 95% capacity. Includes step-by-step calculation and rounding to the nearest cubic meter. Suitable for Grades 7-9.

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