To solve this problem, we need to determine the rate at which the water level in the tank increases and then use this rate to find the height of the water after an additional 2 minutes.

First, let's calculate the rate of increase in the height of the water.

Given:

• The height of the water after 10 minutes is 60 cm.

The rate of increase in the height of the water per minute is: $\text{Rate} = \frac{\text{Height}}{\text{Time}} = \frac{60 \text{ cm}}{10 \text{ minutes}} = 6 \text{ cm/minute}$

Now, we need to find the height of the water after 2 more minutes.

The additional height added in 2 minutes is: $\text{Additional height} = \text{Rate} \times \text{Time} = 6 \text{ cm/minute} \times 2 \text{ minutes} = 12 \text{ cm}$

Therefore, the total height of the water in the tank after 10 + 2 = 12 minutes is: $\text{Total height} = 60 \text{ cm} + 12 \text{ cm} = 72 \text{ cm}$

So, the height of the water in the tank after 2 more minutes will be 72 cm.

Do you want more details or have any questions?

Here are some additional questions you might be interested in:

1. How to calculate the volume of a cuboidal tank given its dimensions?
2. How to convert cm/min to m/hr in terms of flow rate?
3. What is the formula for the volume of water in a tank based on height and cross-sectional area?
4. How to determine the time required to fill the tank completely?
5. What happens to the rate if the tank has a varying cross-sectional area?

Tip: Always double-check your unit conversions to ensure accuracy in your calculations.