A loading dock is supported by two solid concrete piers. The piers are each two feet in diameter and 10 feet high. How many cubic feet of concrete do the two piers contain?

To find the total volume of concrete in the two piers, we'll calculate the volume of one pier and then double it, as both piers are identical.

### Step 1: Calculate the Volume of One Pier
Each pier is a cylinder with:
- Diameter = 2 feet
- Radius = \( \frac{2}{2} = 1 \) foot
- Height = 10 feet

The volume \( V \) of a cylinder is given by:
\[
V = \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height.

Substituting the values:
\[
V = \pi (1)^2 (10) = 10\pi \text{ cubic feet}
\]

### Step 2: Calculate the Total Volume for Two Piers
Since there are two identical piers:
\[
\text{Total volume} = 2 \times 10\pi = 20\pi \text{ cubic feet}
\]

### Step 3: Approximate the Volume
Using \( \pi \approx 3.14159 \):
\[
20\pi \approx 20 \times 3.14159 = 62.8318 \text{ cubic feet}
\]

### Answer
The two piers contain approximately **62.83 cubic feet** of concrete.

Would you like more details or have any questions? 

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Here are some related questions for further exploration:
1. How would the volume change if the piers were 15 feet tall instead?
2. What would be the volume if the diameter of each pier were increased to 3 feet?
3. How many cubic yards of concrete are required if there are more than two piers?
4. How much weight would the concrete add if each cubic foot weighs 150 pounds?
5. How would we calculate the volume if the piers were hollow cylinders?

**Tip:** In problems involving cylinders, remember that the radius is half of the diameter.

Learn how to calculate the total volume of two concrete piers, each 2 feet in diameter and 10 feet high. This geometry problem involves finding the volume of a cylinder using the formula V = πr²h. Perfect for students in Grades 6-8.

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