Math Problem Statement

Use the position function s(t) = –4.9t2 + 200, which gives the height (in meters) of an object that has fallen for t seconds from a height of 200 meters. The velocity at time t = a seconds is given by the following. $ \displaystyle{\lim_{t \rightarrow a}} \text{ }\dfrac{s(a) - s(t)}{a - t} $ At what velocity will the object impact the ground? (Round your answer to two decimal places.) m/s

Solution

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Math Problem Analysis

Mathematical Concepts

Differentiation
Kinematics
Limits
Quadratic Equations

Formulas

s(t) = –4.9t^2 + 200
v(t) = ds/dt = -9.8t
t = sqrt(200/4.9)
Velocity limit formula: lim_{t -> a} [s(a) - s(t)] / (a - t)

Theorems

Derivative as Instantaneous Velocity
Quadratic Roots

Suitable Grade Level

Grades 11-12