Math Problem Statement
over a time interval of 2.27 years, the velocity of a planet orbiting a distant star reverses direction, changing from +18.3km/s to -22.0km/s. Find the total change in the planet's velocity in m/s and its average acceleration in m/s^2 in this time interval
Solution
1. Total Change in Velocity (in m/s):
The total change in the planet's velocity () is the difference between its final velocity and initial velocity. The velocities are given as:
- Initial velocity () = +18.3 km/s
- Final velocity () = -22.0 km/s
Since the velocities are given in km/s, we'll convert them to m/s:
Now, we calculate the change in velocity:
So, the total change in velocity is -40,300 m/s.
2. Average Acceleration (in m/s²):
The average acceleration () is calculated using the formula:
Where:
- (from the previous step),
- .
Let's convert the time interval to seconds and compute the average acceleration.
Now, calculate the average acceleration:
Final Answers:
- Total change in velocity: -40,300 m/s
- Average acceleration: -5.62 × 10⁻⁴ m/s²
Would you like more details on any step?
Here are 5 related questions to extend your understanding:
- How do velocity changes affect the orbit of planets?
- What other methods can be used to measure the velocity of planets?
- How does average acceleration differ from instantaneous acceleration?
- What role does gravity play in reversing the direction of a planet's velocity?
- How can we calculate orbital parameters from velocity and acceleration?
Tip: Always convert time intervals to seconds in physics problems unless otherwise stated.
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Math Problem Analysis
Mathematical Concepts
Kinematics
Velocity Change
Acceleration
Unit Conversion
Formulas
Total Change in Velocity: Δv = vf - vi
Average Acceleration: a_avg = Δv / Δt
Unit Conversions: km/s to m/s, years to seconds
Theorems
Basic Principles of Kinematics
Suitable Grade Level
High School (Grades 11-12)
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