Math Problem Statement

Vector B is angled at 49.0 degrees, and consider vector R which stretches at 36.0 meters

Solution

Given the update:

  • Vector B\mathbf{B} is now angled at 49.0° relative to the positive x-axis, while its magnitude remains the same at 22.0 units.
  • Vector R\mathbf{R} has a magnitude of 36.0 units and aligns along the x-axis (since it stretches horizontally).

Steps to solve:

  1. Recalculate the components of vector B\mathbf{B} with the new angle of 49.0°:

    • Bx=Bcos(49.0)B_x = B \cos(49.0^\circ)
    • By=Bsin(49.0)B_y = B \sin(49.0^\circ)
  2. Determine the components of vector C\mathbf{C} using vectors A\mathbf{A}, B\mathbf{B}, and R\mathbf{R}:

    • Since vector R\mathbf{R} stretches horizontally, it's parallel to the x-axis.
    • The x-component of R\mathbf{R} would then be Rx=36.0R_x = 36.0 units and Ry=0R_y = 0.
  3. Use the vector relationship:

    • Since C\mathbf{C} is parallel to R\mathbf{R}, we need to adjust the relationship to reflect this, possibly adjusting how C\mathbf{C} balances the vector sum to align with R\mathbf{R}.

Let me compute these updated components and the resultant vector C\mathbf{C}.With the updated angle of vector B\mathbf{B} at 49.0°, the magnitude of the resultant vector C\mathbf{C} is approximately 31.22 units, and its directional angle θ\theta relative to the positive x-axis is approximately 32.13°.

This resultant vector C\mathbf{C} aligns with vector R\mathbf{R}, confirming that it is parallel to the x-axis.

Would you like any further details or have any questions?

Here are 5 related questions to explore further:

  1. How would the magnitude of C\mathbf{C} change if vector R\mathbf{R} had a different magnitude?
  2. What would happen to the directional angle if vector B\mathbf{B} had an angle greater than 90°?
  3. How can the vector components be used to analyze the motion of an object in a different scenario?
  4. What is the geometric interpretation of having vectors C\mathbf{C} and R\mathbf{R} parallel?
  5. If vector B\mathbf{B} were to rotate, how would the resultant vector C\mathbf{C} change in magnitude and direction?

Tip: When vectors are parallel, their directional angles are equal or differ by 180°, depending on their direction.

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Math Problem Analysis

Mathematical Concepts

Vectors
Trigonometry

Formulas

Vector components using angles
Magnitude of a vector

Theorems

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Suitable Grade Level

High School