Math Problem Statement
Vector B is angled at 49.0 degrees, and consider vector R which stretches at 36.0 meters
Solution
Given the update:
- Vector is now angled at 49.0° relative to the positive x-axis, while its magnitude remains the same at 22.0 units.
- Vector has a magnitude of 36.0 units and aligns along the x-axis (since it stretches horizontally).
Steps to solve:
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Recalculate the components of vector with the new angle of 49.0°:
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Determine the components of vector using vectors , , and :
- Since vector stretches horizontally, it's parallel to the x-axis.
- The x-component of would then be units and .
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Use the vector relationship:
- Since is parallel to , we need to adjust the relationship to reflect this, possibly adjusting how balances the vector sum to align with .
Let me compute these updated components and the resultant vector .With the updated angle of vector at 49.0°, the magnitude of the resultant vector is approximately 31.22 units, and its directional angle relative to the positive x-axis is approximately 32.13°.
This resultant vector aligns with vector , confirming that it is parallel to the x-axis.
Would you like any further details or have any questions?
Here are 5 related questions to explore further:
- How would the magnitude of change if vector had a different magnitude?
- What would happen to the directional angle if vector had an angle greater than 90°?
- How can the vector components be used to analyze the motion of an object in a different scenario?
- What is the geometric interpretation of having vectors and parallel?
- If vector were to rotate, how would the resultant vector change in magnitude and direction?
Tip: When vectors are parallel, their directional angles are equal or differ by 180°, depending on their direction.
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Math Problem Analysis
Mathematical Concepts
Vectors
Trigonometry
Formulas
Vector components using angles
Magnitude of a vector
Theorems
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Suitable Grade Level
High School
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